Using the Vigenère cipher, encrypt the word “explanation” using the key leg. Hint: You may use a Vigenère Table (shown below) to perform the polyalphabetic encryption process. Remember, a key is needed that is as long as the message.
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Using the Vigenère cipher, encrypt the word “explanation” using the key leg.
Hint: You may use a Vigenère Table (shown below) to perform the polyalphabetic encryption process. Remember, a key is needed that is as long as the message.
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- Consider the game tree in the following figure, where the letter next to the node is the name and the number below the node is the minmax value. Cross out the node(s) whose exact value(s) the alpha-beta pruning method never determines, assuming that the right child is added to the frontier first and the left child is expanded or returns utility (if terminal node) first. Select all nodes with the node names that will be crossed out by the above pruning. MIN ▼ M МАX 11 MIN МАХ АН A G A F A E 13 7 V B ▼ A 14 9. 12GLIDEL. LLISSOTISO SOS 1 S DOOOO99000 OS 11 UID 3 4 1000 2560 4 S 1000 2568 2989 11 11 1 I on 11 S OS S 0 0 0 0 0 0 0 PID 1 2 S 1000 R 1000 S 1000 3243 3392 3459 3498 3519 3520 3525 3527 3542 3513 3570 3571 PPID C PRI NI ADDR SZ UCHAN TTY BOONNNNNN 0 80 0 80 2 0 2 0 2558 0 80 2527 0 80 2 0 60-20 80 20 80 0 20 80 2 0 592 0 0 60 -20 0 0 0 0 0 2 0 80 0 1 0 80 0 592 0 592 0 80 0 80 0 80 0 80 20 80 0 0 2568 0 80 2568 0 80 2568 0 80 TELITIL 43050 Ⓒ 0- 0 43834 ? ? 0 Ⓒ 0 ? ? ? 56050 do_wai tty3 ? ? ? Ⓒ 55239 4331 4331 ? 0 ? 4331 ? ? Ⓒ 55239 hrtime tty3 056323 - tty3 0- 55247 pipe_r tty3 ? tty3 ? TIME CMD 00:00:01 systend 00:00:00 kthreadd 00:00:00 rcu_gp 00:00:00 rcu_par_gp 00:00:00 (sd-pan) 00:00:00 bash 00:00:00 kuorker/u2:2-events_un 00:00:00 kuorker/0:1-events 00:00:00 kuorker/u2:0-ext4-rsu 00:00:00 kuorker/0:2-ata_sff 00:00:00 sleep 00:00:00 systend-uservor 00:00:00 systend-useruor 00:00:00 kuorker/0:0-ata_sff 00:00:00 systend-useruor 00:00:00 kuorker/u2:1-events_un 00:00:00 sleep…3 OrderI addres d custI custNam ВookDat ProdI ВokQt Pric cost S e e y e 1122 123 A10 John 10/2/16 Тр 6 10 2000 2000 main st. Sams 200 1000 3 1001 234 st A20 Sam 11/4/16 ZTC 1 100 2000 gate 2004 989 st A22 Lau 22/5/16 HTC 9 2 2000 4000 mid ZTC 1 100 | 200 Sam 3 1 200 200 The above sales table is from Company XYZ. The company would to build the database to record the form information. You as the database administrator, normalize the above table from 1 Normal Form (1NF), 2NF and 3NF. 20
- Input-1.txt 6 X X X X X O X O X O O X X X O O O X X X X O X X X O X X O O X X X X X X input-2.txt 8 X X X X X O O X X O X O O X O O X X O O O X X X X X X O X X O O X O X X O O O O X X O X X X X O O X O O O O X X X X X X X X X X9. 2 b k 1 m r g n S a C h P d j 9Can you create a logarithmic algorithm using MARIE programming? This is what I have so far ORG 100 INPUT /if you put input x or y, it'll give you an inaccurate numberSTORE XOUTPUTINPUTSTORE YSTORE C1STORE C2OUTPUT LOOP2, LOAD YSUBT ONESTORE YSKIPCOND 400JUMP DIVIDEJUMP LOOP2 DIVIDE, LOAD YSUBT XSTORE Y /REPEATEDLY DO X=X-YSKIPCOND 000JUMP COUNTJUMP LOOP3 COUNT, LOAD ZEROLOAD UADD ONESTORE UJUMP DIVIDE LOOP3, LOAD YSUBT ONESTORE YSKIPCOND 400JUMP LOGJUMP RESULT LOG, LOAD USTORE X/LOAD E/STORE ULOAD C2STORE C1JUMP DIVIDE RESULT, LOAD U /WITHOUT THE RESULT, THIS GOES IN AN INFINTE LOOPOUTPUTHALT X, DEC 0Y, DEC 0U, DEC 0E, DEC 0ONE, DEC 1 I want to know what I'm doing wrong. PLEASE ANSWER IN MARIE
- Q6/ If XY'+Y=X+Y the correct answer O None of them O X'Y'Z+XY=Z+XY XYZ+X'+Y=Z+XY OXY'Z'+Y+Z=X+Y+Z O X'YZ+Y'=XZ+Y' O XYZ'+Y'Z=X+YZ' ChoseNumber of owls: 7 440054 2998504 qx3y7 2 1 total_owls = 0 2 3 num_owls_A = input () 4 num_owls_B = input () 5 6 7 print('Number of owls:', total_owls) Run W ✓ Testing with inputs: 3 4 S → X Not all tests passed 3 e $ 4 C 5 10 V t g . 6 b y h & 7 n O acer 8 I 9 k alt 1 0 р = ctrl 11 ? 1 backspace Halia 1 test 7 panned passed ⒸOUS 4 1 5QI: Find the output of the following in SoF AD AB 00 01 11 10 00 01 1 10 CD 1 12 00 I 12 8 00 4 01 01 13 9. 1. 13 9. 11 1. 15 3. 15 11 10 10 1 14 14 10 Googe Ovone E