Using the DNA figure below to identify structures of the following letters: A= B= C= D= E= F: Circle a nucleotide for each backbone strand A G a (4::( B A G (: G ( E
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- For the following DNA sequence: 3’–CGATACGGCTATGCCGGCATT–5’ Write: a) the sequence of the complementary DNA strandWrite out the DNA sequence using the following instructions: This is a double stranded DNA hydrogen bonding with each other following the principle of complementary base-pairing Each strand contains ten nucleotides Each strand contains all four different types of nucleotides You should indicate clearly the directionality of each strand in your answer You do not need to draw the full nucleotide structure. Use the one-letter code (A, T, G, C, or U) to represent each nucleotideIn a sample solution given to be analyzed;CATAGCTTTGTTAAA (DNA nucleotide chain). Show the 5 'and 3' ends by writing in triplet (codon) form. Find the number of Hydrogen bonds in the double helix DNA strand at the beginning.
- Draw the following trinucleotide: pGAUWhat is the nucleotide sequence of the complementary strand of the DNA molecule: 5’-AATGCGATCTTCAT-3’? Indicate the 5’ and 3’ ends. Follow the same format as the given sequence.Identify the base shown below. Drag the correct base to the rectangle in the image O I HN H₂N Adenine Cytosine N N IZ 5 methyl cytosine H Guanine Thymine
- DNA structure depends on base pairing of its four nucleotides, A, C, T, and G. Nucleotide A pairs with T, and nucleotide C pairs with G. This forms a four-letter DNA “alphabet." Because DNA codes for amino acids in sets of three nucleotides, there are 4 cubed (4'), or 64, possible combinations, coding for 20 different amino acids. What is the best explanation for why there is no selective advantage for DNA to have five nucleotides (e.g., A, C, T, G, and E) with C pairing with either G or functionally equivalent E? It would be impossible to form the DNA molecule, because it must have an equal number of Cs and Gs. Because G and E have the same role, there would still be four functional letters of the alphabet. Replication would be inaccurate because sometimes C would bond with G and sometimes C would bond with E. There would be a five-letter alphabet with 125 combinations, which is too numerous. It is impossible because there are not five known nucleotides in the cell.Identify the base shown below. Drag the correct base to the rectangle in the image O HN H₂N Adenine Cytosine N N N ZI 5 methyl cytosine H Guanine ThymineTranslate this nucleotide sequence into an amino acid sequence. Gene Sequence (5'-to-3'):…
- Place an asterisks (*) next to the 3' carbon atoms in the polynucleotide shown. -O CH₂ HOHDH Guanine -O-CH₂ H H H Thymine =P-O-CH₂ H OH Answer Bank H H CytosineWrite the sequence of reverse compliment chain to this DNA sequence: CGTCCGCCCCGCGAGCACA TGTGCGCGCGGGGCGThere is a chemically synthesized DNA oligonucleotide is 5’–AUCG–3’. Pleasedraw the all-atom structure of this RNA strand, including that of the phosphategroup, the pentose (ribose), and the base for each nucleotide. The structure is inthe 5’→3’ direction