Using the average molarity of the NaOH solution determined from your results in part A, calculate the molarity and percent by mass of the acetic acid in your vinegar sample and report their average values.  H2C2O4•2H2O(s) + 2NaOH (aq)= Na2C2O4 + 4H2O(l)   part A  Mass of oxalic acid analyzed (g)- trial 1- 0.302   trial 2- 0.305 initial buret reading of NaOH (mL)- trial 1-0.31   trial 2- 23.42 final buret reading of NaOH (mL) trial 1- 23.42   trial 2 -46.73 Part B volume of vinegar analyzed (mL), trial 1- 5.00 , trial 2- 5.00  initial buret reading of NaOH (mL), trial 1 -0.00,  trial 2 - 22.73 final buret reading of NaOH (mL) trial 1- 22.73, trial 2- 45.50    There is no molarity of oxalic acid that was used during the experiment given

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Using the average molarity of the NaOH solution determined from your results in part A, calculate the molarity and percent by mass of the acetic acid in your vinegar sample and report their average values. 

H2C2O4•2H2O(s) + 2NaOH (aq)= Na2C2O4 + 4H2O(l)

 

part A 

Mass of oxalic acid analyzed (g)- trial 1- 0.302   trial 2- 0.305

initial buret reading of NaOH (mL)- trial 1-0.31   trial 2- 23.42

final buret reading of NaOH (mL) trial 1- 23.42   trial 2 -46.73

Part B

volume of vinegar analyzed (mL), trial 1- 5.00 , trial 2- 5.00 

initial buret reading of NaOH (mL), trial 1 -0.00,  trial 2 - 22.73

final buret reading of NaOH (mL) trial 1- 22.73, trial 2- 45.50 

 
There is no

molarity of oxalic acid that was used during the experiment given 

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