Using Boyle's Law Demonstrator, the absolute pressure and the volume of air are respectively 61.15 kPa and 0.5 L. When the oil height is decreased by 2 cm, the new absolute pressure becomes 50.95 kPa. So, the new air volume will be approximately equal to: Select one: a. 0.6 L b. 0.4 L c. It can't be found because there are missed given data. d. 0.2 L

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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Using Boyle's Law Demonstrator, the
absolute pressure and the volume of air are
respectively 61.15 kPa and 0.5 L. When the
oil height is decreased by 2 cm, the new
absolute pressure becomes 50.95 kPa. So,
the new air volume will be approximately
equal to:
Select one:
a. 0.6 L
b. 0.4 L
c. It can't be found because there are
missed given data.
d. 0.2 L
Transcribed Image Text:Using Boyle's Law Demonstrator, the absolute pressure and the volume of air are respectively 61.15 kPa and 0.5 L. When the oil height is decreased by 2 cm, the new absolute pressure becomes 50.95 kPa. So, the new air volume will be approximately equal to: Select one: a. 0.6 L b. 0.4 L c. It can't be found because there are missed given data. d. 0.2 L
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