Shown below is a dual-fluid manometer used to measure the pressure of the gas inside of a water tank. You are calibrating the manometer by determining the mercury height L, based on the gas pressure pgas- Given the following conditions of the tank-manometer setup, what will be the height of the mercury, L1 in [cm], when the gas pressure in the tank is 118 kPa? You may assume that the acceleration due to gravity is 9.81 m/s². Patm = 101.3 kPa

I need help mostly with question 4 and 5.

A cylindrical storage tank is 10m high and 25m in diameter.  It is filled to a depth of 9.93 m with oil, having a coefficient of volumetric expansion of 4.4 x 10-4 / °C.  To the nearest degree, how much will the temperature of the oil have to change to completely fill the tank.  Consider only the oil; neglect the expansion of the tank itself. [16.0 °C]

The differential change in pressure p close to the surface of a static fluid is given by the following expression:dp/dy = -3Ap2,where A is a constant, with units of 1/(atm•m), and p is the pressure in atm. The pressure at the surface of the fluid is p(0) = 1 atm, and the coordinate y here is positive upwards with origin at the surface.  An absulute pressure gauge is placed at a depth 0.19m in the fluid. What would be the reading of the pressure gauge in units in atm? you can take the constant A=1(atm.m)^-1