Structural Analysis
6th Edition
ISBN: 9781337630931
Author: KASSIMALI, Aslam.
Publisher: Cengage,
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- PROBLEM 2: The rigid frame shown is unbraced. The members are oriented so that bending is about the strong axis. Support conditions in the direction perpendicular to the plane of the frame are such that Ky = 1.0. The beams are W410 x 85, and the columns are B W250 x 149. A992 steel is used. The axial 4.5 m compressive dead load is 400 kN, and the axial compressive live load is 490 kN. a. Determine the axial compressive design strength of column AB. 5.5 m 6.0 m b. Determine the allowable axial compressive strength of column AB.arrow_forwardA compression member is built up from a W14x90 and a W10x49, both of A992 steel.a. Compute rx and ry for the built-up shape.b. Neglect flexural torsional buckling and compute the available strength for KxL = KyL = 30 feetusing LRFD.arrow_forwardThe rigid frame shown is unbraced. The members are oriented so that bending is about the strong axis. Support conditions in the direction perpendicular to the plane of the frame are such that Ky = 1.0. The beams are W410 x 85, and the columns are W250 × 89. A992 steel is used, Fy=345 mPa. The axial compressive dead load is 750 kN and the axial compressive live load is 900 kN. Use the AISC alignment chart or Magdy I. Salama Formula for Kx. 4.5 m 5.5 m 6.0 m ly Cw Sx mm^2 mm^4 mm^3 1100 1510 A Ix rx Sy ry Zx Zy SECTION m mm^4 mm^3 378 mm^3 mm^3 mm^3 mm^9 1040 713 716 mm mm W250x89 4500 11400 143 W410x85 5500 10800 315 48.4 65.2 1230 574 1730 310 112 171 18 199 40.8 926 Which of the following best gives the axial strength of column AB? Use the NSCP 2015 LRFD specifications. O 2,340 kN 1,647 kN O 2,745 kN O 2,471 kNarrow_forward
- Use 2015 NSCP. A compression member shown below with Fy = 50 ksi 30′ W12 x 87 A992 steel 1. Which of the following most nearly gives the value of critical buckling stress in ksi? 2. Which of the following most nearly gives the nominal strength in kips? 3. Considering ASD. Which of the following most nearly gives the allowable strength in kips? 4. Considering LRFD. Which of the following most nearly gives the design strength in kips?arrow_forwardPERFORMED AS REQUIRED. SHOW YOUR COMPLETE SOLUTION. 4.3-1 Use AISC Equation E3-2 or E3-3 and determine the nominal axial compressive strength for the following cases: a. L = 10 ft b. L=30 ft L W10 x 100 A992 steel FIGURE P4.3-1arrow_forwardThe rigid frame shown is unbraced. The members are oriented so that bending is about the strong axis. Support conditions in the direction perpendicular to the plane of the frame are such that Ky = 1.0. The beams are W410 x 85, and the columns are W250 × 89. A992 steel is used, Fy=345 mPa. The axial compressive dead load is 750 kN and the axial compressive live load is 900 kN. Use the AISC alignment chart or Magdy I. Salama Formula for Kx. B 4.5 m 5.5 m 6.0 m Sx mm^2 mm^4 mm^3 1100 L A Ix Sy Zx Cw ly mm mm^4 mm^3 112 48.4 Zy mm mm^3 mm^3 mm^3 mm19 1040 SECTION ry 65.2 1230 574 713 W250x89 4500 11400 W410x85 5500 10800 315 143 378 1510 171 18 199 40.8 1730 310 926 716 Which of the following best gives the allowable axial strength of column AB? Use the NSCP 2015 LRFD specifications. O 1,647 kN 2,471 kN O 900 kNarrow_forward
- Pls help me answer. Thank you.arrow_forwardCivil engg qusarrow_forwardQ2: Verify that the steel section W12 x 106 can be used for the cantilever beam shown in the Figure (2). Check for flexural strength and deflection only. The beam has lateral support at the ends. The service uniform distributed load includes, wp = 6 k/ft dead load and w₁ = 3 k/ft live load. Use steel A992 and C₁ = 1. A -10 ft- B Fig. (2)arrow_forward
- Situation 1: A built up compression section is shown in the figure below. This forms a non-standard wide flange section. Assume kL = 2.4 m. Use A36 steel. PL 250 mm x 12 mm a) Compute the reduction factor Qs for unstiffened elements. b) Compute the reduction factor Qa for the stiffened elements. c) Compute the safe axial capacity of the section (kN) PL 276 mm x 6 mm PL 250 mm x 12 mmarrow_forwardIn steel design use nscp 2015 i need a complete solutions ty..arrow_forward2. Calculate the internal forces in the bar GF and GD in a roof truss as shownbelow. For each bar, indicate if the internal force is tensile or compressive. Usethe section method (snittmetoden). Point A has simple support and D has rollersupport.arrow_forward
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