Use the probability distribution to complete parts (a) and (b) below. The number of defects per 1000 machine parts inspected Defects 3 4. Probability 0.268 0.289 0.242 0.149 0.036 0.016 (a) Find the mean, variance, and standard deviation of the probability distribution. The mean is . (Round to one decimal place as needed.) The variance is. (Round to one decimal place as needed.) The standard deviation is (Round to one decimal place as needed.)

Suppose that the weight of an newborn fawn is Uniformly distributed between 2.5 and 3.8 kg. Suppose that a newborn fawn is randomly selected. Round answers to 4 decimal places when possible.a. The mean of this distribution is    b. The standard deviation is    c. The probability that fawn will weigh exactly 3.7 kg is P(x = 3.7) =    d. The probability that a newborn fawn will be weigh between 3.1 and 3.4 is P(3.1 < x < 3.4) =    e. The probability that a newborn fawn will be weigh more than 3.36 is P(x > 3.36) =  f. P(x > 2.6 | x < 3.3) =  g. Find the 58th percentile.  solve e,f and g only.

Need A B C

Assume that x has a normal distribution with the specified mean and standard deviation. Find the indicated probability. (Enter a number. Round your answer to four decimal places.) ? = 26; ? = 3.6 P(x ≥ 30) =

Suppose that the weight of an newborn fawn is Uniformly distributed between 2.2 and 3.9 kg. Suppose that a newborn fawn is randomly selected. Round answers to 4 decimal places when possible. The mean of this distribution is   . The standard deviation is   . The probability that fawn will weigh exactly 2.5 kg is    P(x=2.5)=P(x=2.5)=   . The probability that a newborn fawn will be weigh between 2.6 kg and 3.7 kg is    P(2.6<x<3.7)=P(2.6<x<3.7)=   . The probability that a newborn fawn will be weigh more than 3.24 kg is    P(x>3.24)=P(x>3.24)=   . P(x>2.8∣x<3.3)=P(x>2.8∣x<3.3)=   . Find the 45th percentile.   kg

The round off errors when measuring the distance that a long jumper has jumped is uniformly distributed between 0 and 6 mm. Round values to 4 decimal places when possible. a. The mean of this distribution is 3 b. The standard deviation is 1.7321 c. The probability that the round off error for a jumper's distance is exactly 2.7 is P(x = 2.7) = d. The probability that the round off error for the distance that a long jumper has jumped is between 0 and 6 mm is P(1.9 1.5) = f. P(x > 4.7 | x > 1.6) = g. Find the 47th percentile. h. Find the minimum for the upper quartile.

Assume the samples are random and independent, the populations are nomally distributed, and the population variances are equal. The table available below shows the prices (in dollars) for a sample of automobile batteries. The prices are classified according to battery type. At a = 0.10, is there enough evidence conclude that at least one mean battery price is different from the others? Complete parts (a) through (e) below. E Click the icon to view the battery cost data. (a) Let u1. P2. H3 represent the mean prices for the group size 35, 65, and 24/24F respectively. Identify the claim and state Ho and H. H Cost of batteries by type The claim is the V hypothesis. Group size 35 Group size 65 Group size 24/24F 101 111 121 124 D 146 173 182 278 124 140 141 89 (b) Find the critical value, Fo, and identify the rejection region. 90 79 84 The rejection region is F Fo, where Fo = (Round to two decimal places as needed.) (c) Find the test statistic F. Print Done F= (Round to two decimal places as…

Select the statements that describe a normal distribution. Two parameters define a normal distribution—the median and the range. The density curve is symmetric and bell‑shaped. The normal distribution is a discrete distribution. The normal distribution is a continuous distribution. Approximately 5%5% of values fall more than two standard deviations from the mean. The density curve is left‑skewed.

The round off errors when measuring the distance that a long jumper has jumped is uniformly distributed between 0 and 5.8 mm. Round values to 4 decimal places when possible. b. The standard deviation is c. The probability that the round a. The mean of this distribution is off error for a jumper's distance is exactly 0.3 is P(x-03)-d. The probability that the round off error for the distance that a long jumper has jumped is between 0 and 5 8 mm is PC1.7 x 5.2)- that the jump's round off error is greater than 1.76 is P(x > 1.76) Find the 81st percentile. e. The probability f P(x > 1.4 x > 0.6) h. Find the mnmum for the upper quartile.

In a study, 25,000 adults were randomly surveyed as to the number of grandchildren they have, X. The probability distribution is given below. Find the mean and the standard deviation of the probability distribution using a TI-83, TI-83 Plus, or TI-84 graphing calculator. Round the mean to one decimal place and the standard deviation to two decimal places. x P(x) 0 0.01 1 0.02 2 0.02 3 0.24 4 0.35 5 0.20 6 0.07 7 0.05 8 0.02 9 0.01 10 0.01