Use the initial condition y(2) = 7 to determine the value of A that will satisfy the initial value problem. y = Ae* /2-x + 7 7 = Ae²²/2-2 +7 A = 2 y = 2 Substituting this value for A, solve the initial value problem. X

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Using the Initial Condition to Solve for A**

To solve the initial value problem, use the initial condition \( y(2) = 7 \).

**Problem:**

The function is given by:
\[ y = Ae^{x^2/2 - x} + 7 \]

Substitute \( x = 2 \) into the equation using the initial condition:
\[ 7 = Ae^{2^2/2 - 2} + 7 \]

**Evaluating A:**

Attempted calculation for A:
There's an incorrect calculation for A shown as:

\[ A = \frac{2}{e^2} \]

**Substituting value for A:**

A box is provided where the final equation should be placed. However, the calculation and placement are marked with a red cross indicating an error.

\[ y = \] 

The calculation needs to be reviewed to identify and correct the error in determining the value for A, ensuring it satisfies the initial condition provided.
Transcribed Image Text:**Using the Initial Condition to Solve for A** To solve the initial value problem, use the initial condition \( y(2) = 7 \). **Problem:** The function is given by: \[ y = Ae^{x^2/2 - x} + 7 \] Substitute \( x = 2 \) into the equation using the initial condition: \[ 7 = Ae^{2^2/2 - 2} + 7 \] **Evaluating A:** Attempted calculation for A: There's an incorrect calculation for A shown as: \[ A = \frac{2}{e^2} \] **Substituting value for A:** A box is provided where the final equation should be placed. However, the calculation and placement are marked with a red cross indicating an error. \[ y = \] The calculation needs to be reviewed to identify and correct the error in determining the value for A, ensuring it satisfies the initial condition provided.
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