In Calculus you will see the symbol y'. Treat y' as a variable and solve the equation for y. 6y²y + 30xy + 6x²y = 5y² + 25xyy Select one: O a. a. y' O b.y = O c.y = O d. y = = y(y - 6x) 6x² - 5xy + 6y²2 y - 6x 6x² - 5x + 6y 5y(y – x) x² - 25xy + y² 5y(y - 6x) 6x² 25xy + 6y² -

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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In Calculus you will see the symbol y'. Treat y' as a variable and solve the equation for y'.
6y²y + 30xy + 6x²y = 5y² + 25xyy'
Select one:
O a. y
=
O b. y =
=
O c. y'
=
O d.y=
=
y(y - 6x)
6x² − 5xy + 6y²
y - 6x
6x² - 5x + 6y
5y(y – x)
x² - 25xy + y²
5y(y - 6x)
6x² - 25xy + 6y²
Transcribed Image Text:In Calculus you will see the symbol y'. Treat y' as a variable and solve the equation for y'. 6y²y + 30xy + 6x²y = 5y² + 25xyy' Select one: O a. y = O b. y = = O c. y' = O d.y= = y(y - 6x) 6x² − 5xy + 6y² y - 6x 6x² - 5x + 6y 5y(y – x) x² - 25xy + y² 5y(y - 6x) 6x² - 25xy + 6y²
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