Use the following information to answer the next four questions. A manager of a fast-food chain wants to analyze the length of time a vehicle spends at the drive-through window waiting for an order. According to records obtained from the chain, the population mean time spent waiting at the window was 236.5 seconds with a population standard deviation of 34.8 seconds. It is known that the distribution of time waiting at the window is extremely right-skewed. The waiting time was recorded for a random sample of 21 vehicles. For the random sample obtained, the sample mean waiting time was found to be 254.6 seconds with a sample standard deviation of 23.1 seconds. In this example, for the numerical values 236.5 and 254.6 O a. 236.5 is a parameter, 254.6 is a statistic O b. Both are parameters OC. Both are statistics O d. 236.5 is a statistic, 254.6 is a parameter

A researcher thinks that people under forty have vocabularies different from those over sixty years of age. The researcher administers a vocabulary test to a group of 50 younger subjects and a group of 50 older subjects. Higher scores reflect better performance. The mean score for younger subjects was 9.0, and the standard deviation of younger subject's scores was 5.0. The mean score for older subjects was 20.0, and the standard deviation of older subject's scores was 8.0. Does this experiment provide evidence for the researcher's theory? As part of your answer: a. Please provide, in words, the null and alternative hypotheses (NO symbols). Note that you can choose whether to perform a one- or two-tailed test Answer:  Null hypothesis: Alernative hypothesis:   b. Provide a brief (one or two sentence(s) rationale for your decision to use a one or two tailed test Answer   c. Calculate the Standard Error (SE) of the mean difference (demonstrate calculation steps to get an entire point) and…

Mr. Stant collected information on how much customers spend at Walmart and Target. He created the following histograms. Which of the statements must be true about the two data sets displayed?  a The standard deviation of amounts spent at Walmart is less than the standard deviation of the amounts spent at Target.  b The median amount spent at Walmart is equal to the median amount spent at Target.  c The standard deviation of amounts spent at Walmart is more than the standard deviation of the amounts spent at Target.  d The range of amounts spent at Walmart is equal to the range of amounts spent at Target.  e The mean amount spent at Walmart is equal to the mean amount spent at Target.

A marketing firm is doing research for an internet-based company. It wants to appeal to the age group of people who spend the most money online. The company wants to know if there is a difference in the mean amount of money people spend per morith on Internet purchases depending on their age bracket. The marketing firm looked at two age groups, 18-24 years and 25-30 years, and collected the data shown in the following table. Let Population 1 be the amount of money spent per month on internet purchases by people in the 18-24 age bracket and Population 2 be the amount of money spent per month on internet purchases by people in the 25-30 age bracket. Assume that the population variances are not the same. Internet Spending per Month 18-24 Years Answer Mean Amount Spent Standard Deviation Sample Size Step 1 of 2: Construct a 99 % confidence interval for the true difference between the mean amounts of money per month that people in these two age groups spend on Internet purchases. Round the…

According to the U.S. Census, the average adult woman is the United States is 65 inches tall and the standard deviation is 3 inches.  If Zsike is 67 inches tall, what is her z-score?

The average McDonald's restaurant generates $3.6 million in sales each year with a standard deviation of 0.9. Trent wants to know if the average sales generated by McDonald's restaurants in Kentucky is different than the worldwide average. He surveys 27 restaurants in Kentucky and finds the following data (in millions of dollars): 4.1, 2.8, 4.4, 4.5, 5.3, 5, 3.7, 2.9, 3.8, 4.8, 3.6, 2.3, 3.7, 2.9, 2.9, 4, 1.1, 5.2, 2.9, 5, 4, 4, 5.9, 3.2, 2.2, 4.3, 3.8 Perform a hypothesis test using a 3% level of significance. Step 1: State the null and alternative hypotheses. Ho: [? v] ? v На: ? ? v (So we will be performing a Select an answer test.) Step 2: Assuming the null hypothesis is true, determine the features of the distribution of point estimates using the Central Limit Theorem. By the Central Limit Theorem, we know that the point estimates are Select an answer v with distribution mean and distribution standard deviation Step 3: Find the p-value of the point estimate. P( ? v ? v = P( ? ♥ ?…

Two friends, Karen and Jodi, work different shifts for the same ambulance service. They wonder if the different shifts average different numbers of calls. Looking at past records, Karen determines from a random sample of 32 shifts that she had a mean of 4.8 calls per shift. She knows that the population standard deviation for her shift is 1.4 calls. Jodi calculates from a random sample of 40 shifts that her mean was 4.2 calls per shift. She knows that the population standard deviation for her shift is 1.1 calls. Test the claim that there is a difference between the mean numbers of calls for the two shifts at the 0.01 level of significance. Let Karen's shifts be Population 1 and let Jodi's shifts be Population 2.   Step 2 of 3 :   Compute the value of the test statistic. Round your answer to two decimal places.

Russell is doing some research before buying his first house. He is looking at two different areas of the city, and he wants to know if there is a significant difference between the mean prices of homes in the two areas. For the 39 homes he samples in the first area, the mean home price is $⁢176,400. Public records indicate that home prices in the first area have a population standard deviation of $⁢32,930. For the 32 homes he samples in the second area, the mean home price is $⁢181,500. Again, public records show that home prices in the second area have a population standard deviation of $⁢23,835. Let Population 1 be homes in the first area and Population 2 be homes in the second area. Construct a 95% confidence interval for the true difference between the mean home prices in the two areas. Round the endpoints of the interval to the nearest whole number, if necessary. Lowest Endpoint =  upper Endpoint=

Over the first five years of owning her car, Gina drove about 12,700 miles the first year, 15,478 miles the second year, 12,675 the third year, 11,850 the fourth year, and 13,075 the fifth year. a. Find the mean, median, and mode of this data. b. Explain which measure of central tendency will best predict how many miles Gina will drive in the sixth year. a. mean= 12,700; median= 13,156; no mode; the mean is the best choice because it is representative of the entire data set. b. mean= 13,156; median= 12,700; mode= 3,628; the median is the best choice because it is not skewed by the high outlier. c. mean= 13,156; median= 12,700; no mode; the mean is the best choice because it is representative of the entire data set. d. mean= 13,156; median= 12,700; no mode; the median is the best choice because it is not skewed by the high outlier.

Mario's weekly poker winnings have a mean of $353 and a standard deviation of $67. Last week he won $185. How many standard deviations from the mean is that?