**Use technology to find the P-value for the hypothesis test described below.**The claim is that for 12 AM body temperatures, the mean is \(\mu > 98.6^\circ F\). The sample size is \(n = 8\) and the test statistic is \(t = 1.265\).P-value = \(\_\_\_\_\) (Round to three decimal places as needed.)

Name: **Use technology to find the P-value for the hypothesis test describe
Uploaded: 2024-03-20T07:07:00.000Z
Channel: Bartleby
Description: **Use technology to find the P-value for the hypothesis test described below.**The claim is that for 12 AM body temperatures, the mean is \(\mu > 98.6^\circ F\). The sample size is \(n = 8\) and the test statistic is \(t = 1.265\).P-value = \(\_\_\_

Denote μ as the true mean body temperature. Null hypothesis: H0: μ = 98.60F. Alternative hypothesis: H1: μ > 98.60F.Thus, the test is the right tail test. The sample size is n = 8. The degrees of freedom (df) for a one-sample t-test, for a sample of size n is (n – 1). Here, n = 8, so that df = 7 (= 8 – 1). The test statistic is t = 1.265. Now, using the EXCEL formula =T.DIST.RT(1.265,7) the P-value is obtained as approximately 0.123.

Math

Statistics

Use technology to find the P-value for the hypothesis test described below. The claim is that for 12 AM body temperatures, the mean is u> 98.6°F. The sample size is n=8 and the test statistic is t=1.265. P-value = (Round to three decimal places as needed.) !!

Use technology to find the P-value for the hypothesis test described below. The claim is that for 12 AM body temperatures, the mean is u> 98.6°F. The sample size is n=8 and the test statistic is t=1.265. P-value = (Round to three decimal places as needed.) !!

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Suppose you needed to test the claim that the two samples described below come from populations with the same mean. Assume that the samples are independent simple random samples. Sample 1: n1 13, a1 = 24, 81 = 7.55 Sample 2: n2 = 3, x2 = 21.9, 82 = 8.92 Find: (a) The estimated degree of freedom is (b) The standardized test statistic is (use Sample 1 - Sample 2)
Road Transport Department claims that the mean speed of cars on a highway is 114 km/h. An insurance company took a random sample of 21 cars driven on a highway and found that the test statistic is -2.2913. Can we accept the Road Transport Department's claim at 5% level of significance? (Hint: o unknown)
Table 2 on page 603 is based on paired-samples t tests, a technique that we do not cover in this course. However, based on the p-values listed in the second to last column of the table, state three measures that showed a statistically significant change over 24 months for mothers and children in the MST-BSF group. Indicate whether the change was an increase or a decrease, and whether the change was in the mother or the child.?
Records indicate that the mean weight of mature rainbow trout in Eagle Creek is 1.75 kg with a standard deviation of 0.37 kg. After years of marked oxygen depletion from pollutants in the creek, you want to perform a hypothesis test to see if the standard deviation, ơ, of weights has changed. To do so, you measure the weights of 19 randomly chosen mature rainbow trout from the creek and find that the sample standard deviation is 0.49 kg. Under the assumption that current weights of mature rainbow trout in the creek follow a normal distribution, you will perform a chi-square test. Find x, the value of the test statistic for your chi-square test. Round your answer to three or more decimal places. 2
Listed below are systolic blood pressure measurements (mm Hg) taken from the right and left arms of the same woman. Assume that the paired sample data is a simple random sample and that the differences have a distribution that is approximately normal. Use a 0.10 significance level to test for a difference between the measurements from the two arms. Identify the test statistic and p-value. Right arm Left arm 144 167 OA.T-3.07, p-value = 0.037 OB. T = -2.32, p-value = 0.081 OC. T = -1.93, p-value = 0.127 OD. T = -4.01, p-value = 0.016 133 161 132 179 138 145 136 144
Claim: The mean systolic blood pressure of all healthy adults is less than than 121 mm Hg. Sample data: For 272 healthy adults, the mean systolic blood pressure level is 120.59 mm Hg and the standard deviation is 15.61 mm Hg. The null and alternative hypotheses are Ho: I = 121 and H,: I< 121. Question: Find the value of the test statistic.
You'd like to test the null hypothesis that the means of the two samples (column A and column B) are the same. The alternative hypothesis is that they are not the same. You have no reason to believe that the standard deviations of the two samples are equal. Test at the alpha = 0.10 level. After using Excel, what do you conclude? Are the means the same?
Daily Driving The average number of miles a person drives per day is 24. A researcher wishes to see if people over age 60 drive less than 24 miles per day. She selects a random sample of 25 drivers over the age of 60 and finds that the mean number of miles driven is 23.4. The population standard deviation is 4.1 miles. At a = 0.01, is there sufficient evidence that those drivers over 60 years old drive less than 24 miles per day on average? Assume that the variable is normally distributed. Use the critical value method with tables. Part 1 of 5 State the hypotheses and identify the claim with the correct hypothesis. H: u = 24 not claim Η: μ 24 claim The hypothesis test is a one-tailed test. Part: 1/5 Part 2 of 5 Find the critical value(s). Round the answer to at least two decimal places. If there is more than one critical value, separate them with commas. Critical value(s):
The correlation coefficient r is a sample statistic. What does it tell us about the value of the population correlation coefficient ?(Greek letter rho)? You do not know how to build the formal structure of hypothesis tests of ? yet. However, there is a quick way to determine if the sample evidence based on ? is strong enough to conclude that there is some population correlation between the variables. In other words, we can use the value of r to determine if ? ≠ 0. We do this by comparing the value |r| to an entry in the correlation table. The value of ? in the table gives us the probability of concluding that ? ≠ 0 when, in fact, ? = 0 and there is no population correlation. We have two choices for ?: ? = 0.05 or ? = 0.01. (a) Look at the data below regarding the variables x = age of a Shetland pony and y = weight of that pony. Is the value of |r| large enough to conclude that weight and age of Shetland ponies are correlated? Use ? = 0.05. (Round your answer for r to four decimal…
I want to know the answer and detail step by step
Daily Driving The average number of miles a person drives per day is 24. A researcher wishes to see if people over age 60 drive less than 24 miles per day. She selects a random sample of 32 drivers over the age of 60 and finds that the mean number of miles driven is 22.9. The population standard deviation is 3.1 miles. At α=0.05, is there sufficient evidence that those drivers over 60 years old drive less than 24 miles per day on average? Assume that the variable is normally distributed. Use the P-value method with a graphing calculator. Find the P-value. Round it to four decimal places.
You are part of a trivia team and have tracked your team's performance since you started playing, so you know that your scores are normally distributed with u = 88 and a = 15 Recently, a new person joined the team, and you think the scores have changed Sample data is: n = 28, sample mean = 72 Assuming a two tailed test, What is the test statistic (Z)?