Use of reverse curves should be avoided in national highways and main railway lines. This could be due to No opportunity to elevate outer bank at PRC All of these Sudden change of direction is uncomfortable to passengers Sudden change of cant is required from one side of PRC to other

A vertical curve (with EQUAL tangent lengths) is to connect a +1.35% gradient to a -2.25% gradient on a highway designed for a speed of 80 kmph. The K value for the highway is 55 and the minimum required length is to be used. The reduced level and through chainage of the intersection point of the gradients are 78.34 metres and 667.49 metres respectively. i) ii) Calculate the reduced levels and the chainages of the tangent points. Calculate the reduced levels at exact 25 metre multiples of through chainage along the curve. ii) Calculate the through chainage and the reduced level of the highest point on the curve.

Determine variables requested below for a horizontal curve with the following characteristics. Length of curve 1255', Radius 1200', sta of PC 12+00 superelevation rotated about the roadway centerline, 3 lane roadway, 14ft lane width, entire road section normal crown=2%, road design speed3D60 mph, max superelevation=8%. 9) The difference in elevation of LEP and REP at NC, in ft, is: O 0.42 O 1.68 O 2.52 O 3.36

A simple horizontal curve has 35 degrees of curvature and subtends an angle of 110 degrees. If the PC is at station 3 + 65.00 ft, what is the first chord length (ft)  (i.e. the straight line distance between the PC and the first full station)?