U(s) Rts) Select all correct answers. Select one or more: O a. X3(8)/R(s)=-5/S, if U(s)-0 Ob. X3(S)/R(s)=1/(S+5), if U(s)=0 O. R(S)/U(S)-5(S+5)/(S+1) O d. R(s)/U(s)-5(S+1)/(S+5)

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Signal and system problem write on paper and solve with stepwise

The range of the sequence x(n) = 56(n-1) + 26(n+2) – 36(n-4) + 76(n+1) is -2 sns 4

i need the answer quickly

a XCF) = 5 SCF - 2000 +58(f+2000 )+3 6(F-300) + S( F+30) XF) = - 2-58(F-2000) +2-5 6CF+2000) +1-56(F -3000) + Noo the sampled spectaum Expression is 1•5 6(F+3000) Xs (F )= Ę Ž x(f-nfs) = Ss 2 xCfnfs) Ts n=-0 n=-00 - 8000 2 XCF-n8000) %3D nニ-の I need the drawing step by step and each information separately Step 3 of 5:) The spectoum X(F) is 2.5 1.5 11-5 FCKHZ) 2 -3 -2 - 0o to +0 we cam drao spedtoum as On putingn from 2.5x8000 =20,000 12000 2 3 5 6 8 10 I| 13 14 16 18 21 *a 49 -14 -13 - -l0-G -6-5 -3 -2 o 4 KHZ cut off Frequermcy is * output spectoum is 20, O00 12,000 7FCKHZ) -3 -2 Nouo eguation 5 oulput spectrum is yE) = 24000Cos(an x3000t) + 49000 COs(aix2000

What is the unit ramp time response c(t) of the system below? G(s) R(s) a C(s) sta O t-(1/a) - eat O 1- e'at O e at

-21 14 -14 -n - -lo-G -6-5 → XCF) = E S(f - 2000} +58(f+2000 ) +3 6(F-300) +S(F+30) >> XE) = 2-56(f-2000) +2-5 6CF+20) +1•5 6(F -3000) + Noo the sampled spectoum Expaession is l•5 6(F+3000) Xs (F ) = Ę Ž x(f-nfs) = fs 2 xCfnfs) 「Ts nニー0 %3D nニ-の 8000 2 *CF-n8000) こ nニ-の I need the drawing step by step and each information separately Step 3 of 5:) The spectoum XC F) is 2.5 12.5 1.5 11-5 FCKHZ) 3. 2. -2 -3 we cam drao Spectoum as On puttingn from -o to +oo 2.5X8000 =20,000 12005 5 6 8 1o I i3 14 16 18 21 -20 2. FKHE -3 cut tf Frequemcy is AKHZ * out put spectoum is 20, 000 12:000 7FCKHZ) 2. -3 -2 0 NoLo egyuation oulput spectrum is JE)= 24000c0os(2n x3000 t) + 49 O00 Cos(aTI x20 %3D

5 Find the step response for the below given system in figure 01. G(s) = S+10 R(S) G(s) C(s)

Please don't use matlab please answer in typing format