a XCF) = 5 SCF - 2000 +58(f+2000 )+3 6(F-300) + S( F+30)XF) =- 2-58(F-2000) +2-5 6CF+2000) +1-56(F -3000) +Noo the sampled spectaum Expression is1•5 6(F+3000)Xs (F )= Ę Ž x(f-nfs) = Ss 2 xCfnfs)Ts n=-0n=-00- 8000 2 XCF-n8000)%3Dnニ-のI need the drawing step by stepand each information separatelyStep 3 of 5:)The spectoumX(F) is2.51.511-5FCKHZ)2-3-2- 0o to +0we cam drao spedtoum asOn putingn from2.5x8000 =20,00012000235 6 8 10 I| 13 14 16 18 21*a 49 -14 -13 - -l0-G -6-5 -3 -2 o4 KHZcut off Frequermcy is* output spectoum is20, O0012,0007FCKHZ)-3 -2Nouo eguation 5 oulput spectrum isyE) =24000Cos(an x3000t) + 49000 COs(aix2000

Answered: Image /qna-images/answer/ea51162e-baf0-461f-8115-9201cd662da0.jpg

-21 -14 14 -3 -1 -10-G -6-5 -3 -2 o 2 3 Step 3 of 5:) I need the drawing step by step and each information separately The spectoum XC F) is 2.5 12.5 1.5 FCKHZ) -2 2 - 3 we can drauo spedtoum as On puttingn from -o to +oo 2.5X8000 =20,000 12000 5 6 8 1o I| 13 14 16 18 21 FCHE tf Frequency is 4KHZ * output spectrum is 20, O00 12,000 FCKHZ) 3 3 -2 0 2 NoUO equation 5 oulput spectrum is aE) = 240ocos(an x3000t) + 49000 Cos(aTI x 2.000

-21 -14 14 -3 -1 -10-G -6-5 -3 -2 o 2 3 Step 3 of 5:) I need the drawing step by step and each information separately The spectoum XC F) is 2.5 12.5 1.5 FCKHZ) -2 2 - 3 we can drauo spedtoum as On puttingn from -o to +oo 2.5X8000 =20,000 12000 5 6 8 1o I| 13 14 16 18 21 FCHE tf Frequency is 4KHZ * output spectrum is 20, O00 12,000 FCKHZ) 3 3 -2 0 2 NoUO equation 5 oulput spectrum is aE) = 240ocos(an x3000t) + 49000 Cos(aTI x 2.000

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Concept explainers

Quantization and Resolution

Quantization is a methodology of carrying out signal modulation by the process of mapping input values from an infinitely long set of continuous values to a smaller set of finite values. Quantization forms the basic algorithm for lossy compression algorithms and represents a given analog signal into digital signals. In other words, these algorithms form the base of an analog-to-digital converter. Devices that process the algorithm of quantization are known as a quantizer. These devices aid in rounding off (approximation) the errors of an input function called the quantized value.

Probability of Error

This topic is widely taught in many undergraduate and postgraduate degree courses of:

Question

a XCF) = 5 SCF - 2000 +58(f+2000 )+3 6(F-300) + S( F+30)
XF) =
- 2-58(F-2000) +2-5 6CF+2000) +1-56(F -3000) +
Noo the sampled spectaum Expression is
1•5 6(F+3000)
Xs (F )= Ę Ž x(f-nfs) = Ss 2 xCfnfs)
Ts n=-0
n=-00
- 8000 2 XCF-n8000)
%3D
nニ-の
I need the drawing step by step
and each information separately
Step 3 of 5:)
The spectoum
X(F) is
2.5
1.5
11-5
FCKHZ)
2
-3
-2
- 0o to +0
we cam drao spedtoum as
On putingn from
2.5x8000 =20,000
12000
2
3
5 6 8 10 I| 13 14 16 18 21
*a 49 -14 -13 - -l0-G -6-5 -3 -2 o
4 KHZ
cut off Frequermcy is
* output spectoum is
20, O00
12,000
7FCKHZ)
-3 -2
Nouo eguation 5 oulput spectrum is
yE) =
24000Cos(an x3000t) + 49000 COs(aix2000

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