unlv.instructure.com Question 3 Using Hess' law, determine AH for the following reaction: CS2(1) + 3 Cl2(g) -> CCI4(1) + S2CI2(1) Heats of Reaction: CS2(1) + 3 O2(g) --> CO2(g) + 2 SO2(g) AHº/kJ = -1077.0 2 S(s) + Cl2(g) --> S½CI2(1) AH/kJ = -60.2 C(s) + 2 Cl2(g) --> CCI4(1) AH/kJ = -135.4 S(s) +O2(g) --> SO2(g) AH/kJ = -296.9 C(s) +O2(g) --> CO2(g) AH/kJ = -393.5 -285.3 O-297.5 -272.5 -261.3 Question 4 MacBook Pro

unlv.instructure.com Question 3 Using Hess' law, determine AH for the following reaction: CS2(1) + 3 Cl2(g) -> CCI4(1) + S2CI2(1) Heats of Reaction: CS2(1) + 3 O2(g) --> CO2(g) + 2 SO2(g) AHº/kJ = -1077.0 2 S(s) + Cl2(g) --> S½CI2(1) AH/kJ = -60.2 C(s) + 2 Cl2(g) --> CCI4(1) AH/kJ = -135.4 S(s) +O2(g) --> SO2(g) AH/kJ = -296.9 C(s) +O2(g) --> CO2(g) AH/kJ = -393.5 -285.3 O-297.5 -272.5 -261.3 Question 4 MacBook Pro

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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2. Calculate AH for the reaction: CH4 (g) + 4 Cl2 (g) CCI4 (g) +4 HCl (g) Use the following reactions and given AH's. C (s) + 2 H2 (g) C (s) + 2 Cl2 (g) H2 (g) + Cl2 (g) CH4 (g) AH =-74.6 kJ CC14 (g) AH =-95.7 kJ 2 HCl (g) AH =-92.3 kJ 61 shot on moto g' power Crystal H.
Calculate the value of AH for the following reaction: 2 NO₂ (g) N₂O4 (g) → based on the formation reactions for each of the reaction components as shown below: N2 (g) + O2(g) →→→ NO₂ (g) AH = 33.2 kJ/mol N₂ (g) + 2O2 (g) →→→ N₂O4 (g) AH₂ = 11.1 kJ/mol AH: kJ/mol
5. Reaction Enthalpy. balance and calculate AHxn for the following chemical equations. AH (kJ/mol): HCN= 130.5, Ca3(PO4)2=-4120.8, H3PO4--1288, SiCl4=-640.1, SiO2= -910.9, Mg0=-601.6, HCl--167.16 a)NH₂(g) + O₂(g) + CH CH4(g) b)Ca₂(PO4)2(6) +H₂SO4(1) c)SICI(1) + H₂0 (1) d) MgO(s)+ H₂ H₂O(g) SIO₂ (s) + HCN HCN(g) + Caso (s) + H₂PO.(1) Mg(OH)2(s) H₂O(g) HCl(aq)
Calculate the enthalpy change in kJ for the following reaction given the data below. Answer: -610.1 kJ P4O10(g) + 6 PCl5(g) --> 10 Cl3PO(g) A 1/4 P4(s) + 3/2 Cl2(g) --> PCl3(g) Ho/kJ = -306.4 B P4(s) + 5 O2(g) --> P4O10(g) Ho/kJ = -2967.3 C PCl3(g) + Cl2(g) --> PCl5(g) Ho/kJ = -84.2 D PCl3(g) + 1/2 O2(g) --> Cl3PO(g) Ho/kJ = -285.7
Using Hess's law, what is AHf rxn for the following reaction? NO(G) + O(g) – NO2(9) NO(g) + O3(9) – NO2(9) +O2(9) AH xn = -198.8 kJ/mol Og(9) – 3/2 02(9) AHrxn = -142.2 kJ/mol 02(9) → 20(9) AH Prxn = +498.8 kJ/mol -839.8 kJ/mol -306.0 kJ/mol 394.9 kJ/mol 157.9 kJ/mol O 442.3 kJ/mol QUESTION 8 Octane (C3H18) undergoes combustion according to the following thermochemical equation. 2C8H18() + 2502(g) – 16CO2(g) + 18H20() AH°rxn = -1.0940 x 104KJ/mol What is the standard enthalpy of formation of liquid octane? AH°{(CO2(g)) = -393.5 kJ/mol and AH°F{H2O(1)) = -285.8 kJ/mol 495 kl/mol O -250 kJ/mol -495 kJ/mol -10,940. kJ/mol -2188 kJ/mol
N2(g) + O2(g)< -----> 2 NO(g) H = +180.7 kJ 2 H2O(l) <-----> 2 H2(g) + O2(g) H = +571.7 kJ 4 NH3(g) + 5 O2(g) <-----> 4 NO(g) + 6 H2O(l) H = -1167.1 kJ Use Hess's law to calculate H for the reaction below. 2 NH3(g) <-----> N2(g) + 3 H2(g)
A Moving to another question will save this response. Question 2 "A new element (Rr) has been synthesized and its properties analyzed. When 0.132g of RrO (s) is added to 166g of water at 24° Cin a coffee cup calorimeter, the following reaction occurs. RrO(s) + H 20(1) – Rr(OH) 2 (aq) AH = -74.8kJ/mol Given the molar mass for RrO is 62g/mol calculate the following moles of Rro round answer to 4 decimal places omit trailing zeroes 9 rxn in joules round answer to the nearest whole number 9 water in joules round answer to the nearest whole number Final temperature round answer to 1 decimal place omit trailing zeroes A Moving to another question will save this response. Chip
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uestion 27 "A new element (Rr) has been synthesized and its properties analyzed. When 0.157g of RrO (s) is added to 125g of water at 22.2° C in a coffee cup calorimeter, the following reaction occurs. RrO(s) + H 20(1) – Rr(OH) 2 (aq) AH = -83.1k/mol Given the molar mass for RrO is 74g/mol calculate the following moles of Rro round answer to 4 decimal places omit trailing zeroes 9 rxn in joules round answer to the nearest whole number 9 water in joules round answer to the nearest whole number Final temperature round answer to 1 decimal place omit trailing zeroes " A Moving to another question will save this response.
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TUMU Consider these reactions: Reaction 1: H₂(g) + Cl₂(g) → 2HCl(g) AH = -184.6 kJ Reaction 2: 20F 2(g) → O₂(g) + 2 F₂ (g) Reaction 3: N₂(g) +202(g) →→→ 2NO₂(g) Use Reaction 1. Answer: AH = -49.4 kJ Determine the mass, in grams, of chlorine gas consumed (with excess H₂) when 1,152.0 kJ of energy is released from the system. Round to the nearest whole number. g AH = +66.4 kJ
Changes to temperature: Endothermic reaction: Exothermic reaction: 8. reactants + heat products reactants products + heat The reaction: 2SO2(g) + O2(g) 160. AH = positive ΔΗ = negative 2SO3(g) AH= -197kJmoll¹ is discussed on page a) Is the forward reaction exothermic or endothermic? b) Is the reverse reaction endothermic or exothermic? c) What is the endothermic or exothermic reaction favoured when temperature of an equilibrium system is increased? Explain using Le Chatelier's Principle. d) What would happen to the Keg for this reaction at a higher temperature? Why? e) What would happen when the temperature is decreased?