5. Given the following data: + %O2(g) B2H6(g) + 302(g) + ½O2(g) H2O(1) 2B(s) B2O3(s) AH = -1273 kJ/mole B2O3(s) + 3H20(g) H2O(1) H2O(g) AH = -2035 kJ/mole H2(g) AH = -286 kJ/mole %3D AH = 44 kJ/mole Calculate AHrxn for the following reaction: 2B(s) + 3H2(g) B2H6(g) -> + 3/202(g) Reverse (b) B2O3(s) + 3H2O(g) 3x (c) 3H2(g) + 3/202(g) 3H20(1) (a) 2B(s) B2O3(s) B2H6(g) + 302(g) 3H2O(1) 3H20(g) AH = -1273 kJ/mole AH = +2035 kJ/mole %3D AH = -858 kJ/mole %3D Зx (d) AH = 132 kJ/mole 2B(s) + 3H2(g) - B2H6(g) AH = +36 kJ/mole %3D The reaction is ENDOTHERMIC because AH is positive
5. Given the following data: + %O2(g) B2H6(g) + 302(g) + ½O2(g) H2O(1) 2B(s) B2O3(s) AH = -1273 kJ/mole B2O3(s) + 3H20(g) H2O(1) H2O(g) AH = -2035 kJ/mole H2(g) AH = -286 kJ/mole %3D AH = 44 kJ/mole Calculate AHrxn for the following reaction: 2B(s) + 3H2(g) B2H6(g) -> + 3/202(g) Reverse (b) B2O3(s) + 3H2O(g) 3x (c) 3H2(g) + 3/202(g) 3H20(1) (a) 2B(s) B2O3(s) B2H6(g) + 302(g) 3H2O(1) 3H20(g) AH = -1273 kJ/mole AH = +2035 kJ/mole %3D AH = -858 kJ/mole %3D Зx (d) AH = 132 kJ/mole 2B(s) + 3H2(g) - B2H6(g) AH = +36 kJ/mole %3D The reaction is ENDOTHERMIC because AH is positive
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter6: Thermochemisty
Section: Chapter Questions
Problem 6.146QP: Given the following (hypothetical) thermochemical equations:...
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