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Unknown (Lake Water) Lead Concentration. Using the analysis values above, calculate the lead ppb via,

Unknown (Lake Water) Lead Concentration. Using the analysis values above, calculate the lead ppb via,

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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both questions already have the answers but it need's me to show all the work and I don't know how to put it togther or in other words how to show the work for both questions. :)

3. Unknown (Lake Water) Lead Concentration. Using the analysis values above, calculate the lead ppb via, Cu b283 Cs mVu Show all work by presenting your calculation in a clear, organized manner. First state symbolically the equation used, then present the calculation in which actual values are substituted in and the results shown. Remember this format for future calculations. It is recommended to carry the calculation to four significant figures to avoid rounding errors and round to the correct SF at the end. b283= 0.1952 Cs= 4.96 ppb m= 0.02972 ,= 10 mL Vu= Cu 0.1952 x 4.96 0.0297 x 10 Cu= 3.257712
Transcribed Image Text:3. Unknown (Lake Water) Lead Concentration. Using the analysis values above, calculate the lead ppb via, Cu b283 Cs mVu Show all work by presenting your calculation in a clear, organized manner. First state symbolically the equation used, then present the calculation in which actual values are substituted in and the results shown. Remember this format for future calculations. It is recommended to carry the calculation to four significant figures to avoid rounding errors and round to the correct SF at the end. b283= 0.1952 Cs= 4.96 ppb m= 0.02972 ,= 10 mL Vu= Cu 0.1952 x 4.96 0.0297 x 10 Cu= 3.257712
4. Unknown (Lake Water) Lead Analysis Sample Standard Deviation. Calculate the sample standard deviation (S) for the standard addition lead analysis using, Cu= 3.257712= 3.258 = 0.000364 = 3.64 x 10-4 Sm= m= 0.02972 =0.0297 Show all work by presenting your calculations in a clear, organized manner. Remember to first state symbolically the equation, then present the calculation with actual values substituted in and the result shown. It is recommended to carry the calculation to four significant figures to avoid rounding errors and only round to the correct SF at the end. Sp=0.004463 = 4.46 x 10-³ Sc = Cu b283 0.1952 = Sc= 0.1247 (² + Sp 2
Transcribed Image Text:4. Unknown (Lake Water) Lead Analysis Sample Standard Deviation. Calculate the sample standard deviation (S) for the standard addition lead analysis using, Cu= 3.257712= 3.258 = 0.000364 = 3.64 x 10-4 Sm= m= 0.02972 =0.0297 Show all work by presenting your calculations in a clear, organized manner. Remember to first state symbolically the equation, then present the calculation with actual values substituted in and the result shown. It is recommended to carry the calculation to four significant figures to avoid rounding errors and only round to the correct SF at the end. Sp=0.004463 = 4.46 x 10-³ Sc = Cu b283 0.1952 = Sc= 0.1247 (² + Sp 2
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