Unbound granular materials have stress-hardening properties. a. True b. False 32. Fine-grained materials have stress-hardening properties. a. True b. False
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- Fatigue strength for non- ferrous materials in defined at stress cycles 10^3 10^5 10^7 10^9Strain = 600 Stress = Strain = 500 Stress = 400 500 300 400 300 200 200 100 100 0.000 0.002 0.004 0.006 Strain 0.00 0.04 0.08 0.12 0.16 0.20 Strain Stress (MPa)Two triangular wedges are glued together as shown in the figure. The stress acting normal to the interface, o, is MPa. 100 MPa 100 MPa on 45% 100 MPa -100 MPa
- Time len A material has the stress-strain behavior shown in the Figure below. Calculate the toughness (T) of this material. given that S1=195 Mpa; S2=243.75 Mpa; El=0.19; E2=0.38 E1 Strain E2 Stress - Strain diagram of a metal alloy OA.T= 18.52 Mpa O B.T= 92.62 Mpa O C.T= 37.05 Mpa O D.T= 60.21 Mpa Stress (Mpa) 3In a tensile test on a metal specimen having a cross section 20 mm by 10 mm elastic breakdown occurred at a load of 70 000 N. A thin plate madec from the same material is to be subjected to loading such that at a certain point in the plate the stresses are o,=-70 N/mm², 7.y= 60 N/mm² and o. Determine the maximum allowable values of o, using the Tresca and von Mises theories of elastic breakdown. Ans. 259 N/mm² (Tresca), 294 N/mm² (von Mises).The principle stresses (FA, FB, and Fc) shown in the three element figures below are each slowly increased until material yield. Order the principle stresses (FA, FB, and Fc) from lowest to highest (determine which element yields first, which yields second, and which yields third). Fc Fc Fe FA Fa Fc FB
- A 5-mm-thick rectangular alloy bar is subjected to ajtensile load P by pins at A and B, as shown in the figure. The width of the bar is w = 33 mm. Strain gages bonded to the specimen measure the following strains in the longitudinal (x) and transverse (y) directions: €, =710 με and ε,--255 με (a) Determine Poisson's ratio for this specimen. (b) If the measured strains were produced by an axial load of P = 24 kN, what is the modulus of elasticity for this specimen? Answers: (a) v= (b) E= GPaS Figure P1.16 shows the stress-strain relations of metals A and B during ten- sion tests until fracture. Determine the following for the two metals (show all calculations and units): a. Proportional limit b. Yield stress at an offset strain of 0.002 m/m. c. Ultimate strength d. Modulus of resilience e. Toughness f. Which metal is more ductile? Why? 900 Metal A 600 Metal B 300 0.00 0.02 0.04 0.06 0.08 0.10 0.12 0.14 Strain, m/m FIGURE P1.16 Stress, MPaDraw a tensile stress-strain curve for a typical semi-crystalline polymer such as LLDPE, and define the three main regions on the curve.
- A copper rod is deformed using a uniaxial tensile force of 16000 N. Deformation continues until sufficient strain hardening has occurred such that the applied force is too small to allow further deformation. After deformation, the rod has a diameter of 0.01 m and a length of 1.5 m. Assume that copper follows the strain hardening lawwith K of 310 MPa and n=0.54 Please calculate the true strain after the deformation ?A test is conducted on a beam loaded by end couples. The fibres at layer CD are found to lengthen by 0.03 mm and fibres at layer AB shorten by 0.09 mm is 20 mm gauge length as shown in the figure. Taking E-2×10 N/mm², the flexural stress at top fibres would be CD A B 50 mm 100 mm (a) 900 N/mm² tensile (b) 1000 N/mm² tensile (c) 1200 N/mm² tensile (d) 1200 N/mm² compressive →→ 75 mm5) A single zinc crystal is loaded in tension with the normal to its slip plane at 60° to the tensile axis and the slip direction at 40° to the tensile axis. a) Calculate the resolved shear stress when a tensile stress of 0.69 MPa is applied. b) What tensile stress is necessary to reach the critical resolved shear stress of 0.94 MPa?