uestion: Number of hours spent exercising in attempt to improve energy level. Average energy level score (higher=better) of the 45 employees who reported enough hours was 89. The mean energy level score for all employees was 85, with a standard deviation of 6.1. (a) One or Two Tailed? I believe it is one-tailed because it shows direction (improve) (b) Calculate the standard error of the mean. x̄ = 89 N = 56 µ = 85 σ = 6.1 I calculated the degree of freedom: df = N-1 = 56-1 = 55 I calculated the the critival value zcv :(1-tail, alpha = 0.5): 0.2108 I calculated the standard error of the mean σx̄ = σ/√N = 6.1/√56 = 6.1/7.48 = 0.82 I calculated the z test zobt = x̄ − µ/σ = σx̄ = 89-85/0.82 = 4.88 zobt ˃ zcv (4.88 ˃ 0.21) Which would mean that We would reject the H0. I am not sure that I am using the right values....
Question: Number of hours spent exercising in attempt to improve energy level.
Average energy level score (higher=better) of the 45 employees who reported enough hours was 89. The mean energy level score for all employees was 85, with a standard deviation of 6.1.
(a) One or Two Tailed? I believe it is one-tailed because it shows direction (improve)
(b) Calculate the standard error of the mean. x̄ = 89 N = 56 µ = 85 σ = 6.1
I calculated the degree of freedom: df = N-1 = 56-1 = 55
I calculated the the critival value zcv :(1-tail, alpha = 0.5): 0.2108
I calculated the standard error of the mean σx̄ = σ/√N = 6.1/√56 = 6.1/7.48 = 0.82
I calculated the z test zobt = x̄ − µ/σ = σx̄ = 89-85/0.82 = 4.88
zobt ˃ zcv (4.88 ˃ 0.21) Which would mean that We would reject the H0.
I am not sure that I am using the right values....
(c) Conduct the z-test (use at least two decimal places throughout)
(d) what is the zobt score?
(e) What is the zcv?
(f) Write your conclusion in APA format. Did you accept or reject the H0?
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