ty2 values for the degradation of chlorophyll-a in canned green beans heated at various temperatures Temperature ("C) t1/2 values (min) 105 22.6 115 4.2 125 1.2 Find out the z value for the degradation of chlorophyll-a in canned green beans at 105°- 125°C.
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- Aerobic degradation of an organic compound by mixed cultureof organism in wastewater can be represented by following reaction. C3H6O3 + a O2 + b NH3 → c C5H7NO2 + d H2o + e CO2 A. Determine a, b, c, d and e, if YX/S = 0.4 d X/g S. B. Determine the yield coefficients YX/O2 and YX/NH3. C. Determine the degree of reductions for the substrate, bacteria and RQ for the organismsA bacterial culture is grown using either octadecane (C18H38) or pentachlorophenol (C6HOCI5)) as the sole source of carbon and energy. The cell yield value is determined by dry weight analysis to be 1.49 for octadecane and 0.05 for pentachlorophenol. Using either octadecane or pentachlorophenol, please describe the steps taken (and the final result) showing what percentage of the substrate carbon will be found as cell mass and as CO2?A bacterial culture is grown using either octadecane (C18H38) or pentachlorophenol (C6HCl5O) as the sole source of carbon and energy. The cell yield value is determined by dry weight analysis to be 1.49 for octadecane and 0.05 for pentachlorophenol. Using either octadecane or pentachlorophenol, please describe the steps taken (and the final result) showing what percentage of the substrate carbon will be found as cell mass and as CO2? Please show all calculations.
- A bacterial culture is grown using either octadecane (C18H38) or pentachlorophenol (C6HOCl5)) as the sole source of carbon and energy. The cell yield value is determined by dry weight analysis to be 1.49 for octadecane and 0.05 for pentachlorophenol. Using either octadecane or pentachlorophenol, please describe the steps taken (and the final result) showing what percentage of the substrate carbon will be found as cell mass and as CO2? Please show all calculations and give correct answers.A bacterial culture is grown using either octadecane (C18H38) or pentachlorophenol (C6HOCl5)) as the sole source of carbon and energy. The cell yield value is determined by dry weight analysis to be 1.49 for octadecane and 0.05 for pentachlorophenol. Using either octadecane or pentachlorophenol, please describe the steps taken (and the final result) showing what percentage of the substrate carbon will be found as cell mass and as CO2? Please show all calculations and give correct answers. Please answer the question.Calculate the reduction potential of cytochrome a3 (°' = 0.385 V) at 25.0°C when the Fe3+ form = 87.0 μM and the Fe2+ form = 25.0 μM. 0.440 V 0.353 V 0.417 V 0.387 V
- Chitinase is a protein that breaks down chitin, a primary component of the cell wall in fungi, scales in fish and exoskeletons of arthropods. The activity of chitinase extracted from a plant was shown to be optimum at pH 5. You were tasked to prepare 300 mL of 150 mM buffer solution for further analysis of the extracted chitinase. REAGENTS Ka 2.5M Acetic acid Solid NaOAc•3H2O [136.08g/mol] 1.76 x 10-5 2.5M NH3 Solid NH4Cl [53.49g/mol] 5.6 x 10-10 2.5M Lactic acid Solid sodium lactate [112.06g/mol] 4.0 x 10-5 5 M HCl 5M NaOH Pls show sol'ns 1. Given the following reagents, give the moles of each component (acid & base).2. What are the mass/volume of the components needed to prepare the buffer? 3. What will the pH of the buffer be if 1mL of 5 M NaOH was added?Determine the extent of advantage in terms of G factor reduction if a kraft cooking temperature is reduced from 1700C to 1650C, keeping the target H factor constant at1200 (at the cooking temperature) in both cases. The activation energies for the two processes are 32 and 40.3 kcal/mole.Staphylococcal nuclease has a ΔΔG‡ of -84.1 kJ mol-1 at 25.0 °C. If the uncatalyzed rate is 0.630x10-13 µmol s-1, calculate the enzyme-catalyzed rate in µmol s-1. (Use R = 8.3145 J mol-1 K-1)
- The effect of temperature on the hydrolysis of lactose by a ß-galactosidase is shown below in Table 1. The temperature coefficient, Q10 is the factor by which the rate increases by raising the temperature 10°C. The universal gas constant, R is 8.314 J/mol.K. (a) (b) Table 1: Data of Vmax over temperature T (°C) 20 30 35 40 45 Vmax (umoles/min.mg protein) 4.50 8.65 11.80 15.96 21.36 Plot the graph of In Vm vs 1/T using any spreadsheet software (include all appropriate labels and equation). Calculate the activation energy Ea and temperature coefficient Q10.These are SIM media. What does SIM stand for? Describe the reactions in Tubes A, B, C, D, E.i) Re-arrange the Michaelis Menten equation so it involves the ratio [S]. Show all steps beginning Km noting any assumptions or required conditions. Km ii) Calculate the ratio [lo for the case when the rate of product formation is 68% of Vmax and the substrate is in great excess. d[P] dt : k₂ with = [E],[S] Km+[S]' [S]o Km iii) Explain, in a few sentences, why the ratio determines the ratio V Vmax V Vmax Begin by explaining the meaning of stating simply "it's the ratio...." is not sufficient. Include in your explanation the factors that effect v and Vmax. Consider what factors make v different from or equal to Vmax. Consider what Km represents concerning processes involving ES. " iv) Calculate KM at 310K at given the following rate constant information: k₁ = 17 s-¹M-1 at 300K with A = 7300 s-¹M-1 K-1₁ 6 s¹ at 300K with A = 14500 s -1 k₂ = 31 s¹ at 300K with A = 600 s-¹