Two rods A and B of lengths L and  L/2,  respectively, are arranged as shown in the diagram below where  d = L/2.  Here,  L = 2.40 m  and the charge on rod A is 30.5 µC. If the net electric field at the midpoint between the two rods is zero, what is the charge (magnitude and sign) on rod B? The field at a distance y on the perpendicular bisector of a rod of length L is given by  Erod =  2kq y   L2 + 4y2

I need help with part b, please! Point charges of 30.0 µC and 45.0 µC are placed 0.650 m apart. (a) At what point (in m) along the line between them is the electric field zero? ANSWER: 0.292 m away from the 30.0 µC charge (b) What (in N/C) is the electric field halfway between them? (Enter the magnitude.) ______N/C

You have the same line of charge in the previous problem (with +6.00 nC of charge on it).  But now you are measuring the electric field 1.5 m above the center of the rod – see image below.  Predict the electric field at Point P in this diagram.  Make sure to include a direction with your answer.

A thin rod is bent into a half circle of radius R and centered on the y-axis so that it lies flat in the xy-plane as indicated in the diagram. This glass rod is rubbed all over with silk so that the rod has a total positive charge Q uniformly distributed over the length of the bent rod. Answer the following questions to determine the net electric field at an observation location A located on the positive z-axis a distance d from the origin. (See pic 1 for the following questions)  A. Consider an infinitesimal piece of the glass rod located at an angle θ\thetaθ from the positive x-axis. Determine the relative position vector that points from this piece of the rod to the observation location. B. Derive an expression for the electric field dE⃗ of the infinitesimal piece dQ located at angle θ and integrate over the charge distribution to determine the net electric field E⃗ at the observation location. Your answer should only contain the given variables (R, Q, d) and known…

Express answer/s in mks (SI) . Draw diagram whenever necessary Three charges are placed on three corners of a square, as shown in the figure. Each side of the square is24.0 cm. Compute the magnitude and direction of the electric field at the fourth corner.

We have calculated the electric field due to a uniformly charged disk of radius R, along its axis. Note that the final result does not contain the integration variable r: R. Q/A 2€0 Edisk (x² +R*)* Edisk perpendicular to the center of the disk Uniform Q over area A (A=RR²) Show that at a perpendicular distance R from the center of a uniformly negatively charged disk of CA and is directed toward the disk: Q/A radius R, the electric field is 0.3- 2€0 4.4.1b

A uniformly charged rod of length L and total charge Q lies along the x axis as shown in in the figure below. (Use the following as necessary: Q, L, d, and ke.) Ey= P d Ⓡ (a) Find the components of the electric field at the point P on the y axis a distance d from the origin. Ex= Eyz (b) What are the approximate values of the field components when d >> L? Ex L Explain why you would expect these results. This answer has not been graded yet. Need Help? Read It

Three point charges are located on a circular arc as shown in the figure below. (Take r = 4.40 cm. Let to the right be the +x direction and up along the screen be the +y direction.) +3.00 nC -2.00 nC r 30.0° = 30.0° +3.00 nC P (a) What is the total electric field at P, the center of the arc? E= = ÎN/C + ĴN/C (b) Find the electric force that would be exerted on a -4.75-nC point charge placed at P. F ÎN + ĴN CTICE

Two point charges are located on a horizontal line as Shown in diagram on the right. The first small circle Represents the charge Q1 the left and small circle on right Q2 . In the middle between the two charges is point P. a) Find the net electric field due to the 2 charges at point P by finding the magnitude and direction of each one if Q1 =3μC and Q2 =5μC and distance between charges = 50 cm.