A circular rod has a radius of curvature R = 9.01 cm and a uniformly distributed charge Q = 6.62 pC and it subtends an angle θ = 2.40 rad. What is the magnitude of the electric field that Q produces at the center of curvature?_________N/C (please include units so that I can follow the steps easier)

You have the same line of charge in the previous problem (with +6.00 nC of charge on it).  But now you are measuring the electric field 1.5 m above the center of the rod – see image below.  Predict the electric field at Point P in this diagram.  Make sure to include a direction with your answer.

A thin rod is bent into a half circle of radius R and centered on the y-axis so that it lies flat in the xy-plane as indicated in the diagram. This glass rod is rubbed all over with silk so that the rod has a total positive charge Q uniformly distributed over the length of the bent rod. Answer the following questions to determine the net electric field at an observation location A located on the positive z-axis a distance d from the origin. (See pic 1 for the following questions)  A. Consider an infinitesimal piece of the glass rod located at an angle θ\thetaθ from the positive x-axis. Determine the relative position vector that points from this piece of the rod to the observation location. B. Derive an expression for the electric field dE⃗ of the infinitesimal piece dQ located at angle θ and integrate over the charge distribution to determine the net electric field E⃗ at the observation location. Your answer should only contain the given variables (R, Q, d) and known…

PLEASE ANSWER ALL PARTS ASAP!!!!!!!!