Two resistors have resistances R(smaller) and R(larger), where R(smaller) < R(larger). When the resistors are connected in series to a 12.0-V battery, the current from the battery is 1.37 A. When the resistors are connected in parallel to the battery, the total current from the battery is 12.0 A. Determine the two resistances.

The circuit below contains two real batteries, each having significant internal resistance. Battery #1 has an EMF of 6.00 V and an internal resistance of 1.00 ohm. Battery #2 has an EMF of 12.00 V and an internal resistance of 2.00 ohms. These two batteries are connected in series with two resistors R, = 6.00 ohms and R,= 3.00 ohms. ri d (6.00,V) (1.00 0) R1 (6.00 N) R2 (3.00 N) a r2 E2 (2.00 Q) (12.00 V) 18. The current in the 12.00 Volt battery is equal to C. 0.500 A. A. 0.750 A. B. 1.00 A. D. 2.00 A. E. 1.50 A. 19. The potential difference across the terminals of battery #1 from point C to point d is equal to C. 7.00 V. A. 5.50 V. B. 6.00 V. D. 5.00 V. E. 6.50 V. 20. The potential difference across the terminals of battery #2 from point a to point b is equal to C. 13.00 V. A. 14.00 V. В. 10.00 V. D. 11.0 V. E. 12.00 V.

The free-body diagram that best represents the forces acting on the student sliding down a rough incline is (1) (2) (3) (4) (5)

help with this question.

Two resistors, R, = 2.57 2 and R, = 5.81 2, are connected in series to a battery with an EMF of 24.0 V and negligible internal resistance. Find the current I, through R1 and the potential difference V½ across R2. I = A R2 V½ = V

Three resistors of resistances R1 = 11.3, R2 = 50.6, and R3 = 83.4 are connected in series with a 15.1 V battery. How much current (IT) runs through the circuit?