Two resistors have resistances R(smaller) and R(larger), where R(smaller) < R(larger). When the resistors are connected in series to a 12.0-V battery, the current from the battery is 1.15 A. When the resistors are connected in parallel to the battery, the total current from the battery is 11.6 A. Determine the two resistances.

A 597×10−6 F597×10−6 F capacitor is discharged through a resistor, whereby its potential difference decreases from its initial value of 86.9 V86.9 V to 26.1 V26.1 V in 4.11 s4.11 s. Find the resistance ?R of the resistor.

Consider the following circuit diagram. The potential difference across the battery is 40.0 volts, and it supplies a current of 5.00 amperes to the circuit. There is a current of of 2.70 amperes flowing through R1. Resistor R2 has a resistance of 5.50 ohms. What is the resistance of R3? Answer in ohms to two decimal places, but do not include units in your answer.

The circuit below contains two real batteries, each having significant internal resistance. Battery #1 has an EMF of 6.00 V and an internal resistance of 1.00 ohm. Battery #2 has an EMF of 12.00 V and an internal resistance of 2.00 ohms. These two batteries are connected in series with two resistors R, = 6.00 ohms and R,= 3.00 ohms. ri d (6.00,V) (1.00 0) R1 (6.00 N) R2 (3.00 N) a r2 E2 (2.00 Q) (12.00 V) 18. The current in the 12.00 Volt battery is equal to C. 0.500 A. A. 0.750 A. B. 1.00 A. D. 2.00 A. E. 1.50 A. 19. The potential difference across the terminals of battery #1 from point C to point d is equal to C. 7.00 V. A. 5.50 V. B. 6.00 V. D. 5.00 V. E. 6.50 V. 20. The potential difference across the terminals of battery #2 from point a to point b is equal to C. 13.00 V. A. 14.00 V. В. 10.00 V. D. 11.0 V. E. 12.00 V.