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Transcribed Image Text:**Problem Statement:**
Two resistors connected in series have an equivalent resistance of 813.6 Ω. When they are connected in parallel, their equivalent resistance is 123 Ω. Find the resistance of each resistor.
**Inputs:**
- (small resistance) Ω
- (large resistance) Ω
**Explanation:**
- The series connection total resistance is the sum of both resistors: \(R_1 + R_2 = 813.6 \, \Omega\).
- The parallel connection total resistance is given: \(\frac{1}{R_1} + \frac{1}{R_2} = \frac{1}{123} \, \Omega\).
**Hints:**
1. Use the formula for series resistance: \(R_{\text{series}} = R_1 + R_2\).
2. Use the formula for parallel resistance: \(\frac{1}{R_{\text{parallel}}} = \frac{1}{R_1} + \frac{1}{R_2}\).
3. Solve these equations to find \(R_1\) and \(R_2\).
**Input Boxes:**
- Ω (small resistance)
- Ω (large resistance)
**Status:**
- Incorrect (as indicated by the red cross next to the first input box).
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