College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- Consider a ring of charge in the x-y plane of radius 2.7 m, centered at the origin. The charge per angle around the ring is given by dQ/dα = a (1 - cos α) (nC/rad), where a = 8.4 nC/rad. Calculate the electric potential along the z axis at z = 5.8 m, in V. Use k = 9 x 109 N m2 / C2. (Please answer to the fourth decimal place - i.e 14.3225)arrow_forwardAlong the x-axis, the potential is given by: V(x) = 2.16 - 0.251x - 0.137x where x is in meters, and V is in Volts. Find the acceleration if a proton as it passes through the point (0.316 m, 0), 2 in m/s. The sign of the answer will give the direction of the force.arrow_forwardThe three charges in the figure below are at the vertices of an isosceles triangle. Let q = 3.50 nC and calculate the electric potential in KV at the midpoint of the base. (Let d1 = 1.00 cm and d2 = 7.00 cm.)arrow_forward
- (a) Find the electric potential, taking zero at infinity, at the upper right corner (the corner without a charge) of the rectangle in the figure. (Let x = 6.60 cm and y = 2.50 cm.) V(b) Repeat if the 2.00-µC charge is replaced with a charge of −2.00 µC. Varrow_forwardAn electron moving parallel to the x axis has an initial speed of 5.18 x 106 m/s at the origin. Its speed is reduced to 1.68 x 105 m/s at the point x = 2.00 cm. (a) Calculate the electric potential difference between the origin and that point. Volts (b) Which point is at the higher potential? O the origin O the point x = 2.00 cm O both have the same potentialarrow_forward(a) The electric potential in a region is given by the equation V(x, y) = (1.00) xyz +2.00v. sin (3.00-x). What is the force on a 65.4 mC located at position (3.30 m, 4.21 m,-1.80 m)? Give your answer in vector component notation. (b) The electric potential in a region is given by the equation V(x, y, z) = (2.40)x²y + (1.5 V)e (1.002). What is the force on a 12.6 mC located at position (-1.30 m, 2.48 m,-2.10 m)? Give your answer in vector component notation.arrow_forward
- An electron moving parallel to the x axis has an initial speed of 3.40 x 106 m/s at the origin. Its speed is reduced to 1.98 x 105 m/s at the point x = 2.00 cm. (a) Calculate the electric potential difference between the origin and that point. Volts (b) which point is at the higher potential? O the point x = 2.00 cm ● the origin O both have the same potentialarrow_forwardOver a certain region of space, the electric potential is V = 4x - 5x²y + 8yz². (a) Find the expressions for the x, y, z components of the electric field over this region. (Use any variable or symbol stated above as necessary.) Ex Ey Ez = = = (b) What is the magnitude of the field at the point P that has coordinates (1.00, 0, -6.00) m? N/Carrow_forwardDetermine the magnitude of an electric field at a point in space given by r = (1.00 m i, 1.50 m j, -1.00 m k) if the electric potential is given by where x, y, z are in meters and V in volts.arrow_forward
- Consider the following figure. (a) Find the electric potential, taking zero at infinity, at the upper right corner (the corner without a charge) of the rectangle in the figure. (Let x = 5.70 cm and y = 3.50 cm.) (b) Repeat if the 2.00-µC charge is replaced with a charge of −2.00 µC.arrow_forwardTwo protons are located at (4.70, 0) m and (0, 2.90) m, respectively. Determine the following. (a) the electric potential at the origin V (b) the electric potential energy of a third proton located at the origin Jarrow_forwardA Uniform electric field of magnitude 300 N/m is directed parallel to the +X axis. The electric potential at the origin is equal to 150 volts. Determine the electric potential: on x-axis at x = 15 cm and x = -15 cm on y-axis at Y = 6 cm at point (6 cm, 4.5 cm)arrow_forward
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