Álong the x-axis, the potential is given by: V(x) = 2.16 - 0.251x - 0.137x where x is in meters, and V is in Volts. Find the acceleration if a proton as it passes through the point (0.316 m, 0), in m/s“. The sign of the answer will give the direction of the force.

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Chapter1: Units, Trigonometry. And Vectors
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Along the x-axis, the potential is given by:
V(x) = 2.16 - 0.251x - 0.137x where x is in meters, and V is in Volts.
Find the acceleration if a proton as it passes through the point (0.316 m, 0),
2
in m/s. The sign of the answer will give the direction of the force.
Transcribed Image Text:Along the x-axis, the potential is given by: V(x) = 2.16 - 0.251x - 0.137x where x is in meters, and V is in Volts. Find the acceleration if a proton as it passes through the point (0.316 m, 0), 2 in m/s. The sign of the answer will give the direction of the force.
Expert Solution
Step 1

The electric field is the negative gradient of electric potential. The electric field is given by,

Ex=-dVxdx=-d2.16-0.251x2-0.137xdx=--0.502x-0.137=0.502x+0.137

The electric field at the point 0.316 m, 0 is found as,

E=0.5020.316+0.137=0.2956 N/C

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