Two point charges, Q1=-1 nC and Q2=6 nC are placed 5 cm apart as shown above. Determine the magnitude and direction of the resultant electric field strength at point M where b=7 cm following the step below. I) Draw the electric field strength at point M II) Find r1M and r2M Find E1=kQ1/r1M2 and E2=kQ2/r2M2 III) Find x and y component of E1 and E2 and put it in the table. IV) Find EMx and EMy Then, find EM and the

Q3) Two point charges (Q = + 5.0 µC and Q2 = – 2.0 µ C) are held in place along the x-axis. Q, is at x1 = - 3.0 cm and Q, is at x2 = + 2.0 cm. a) Determine the electric field at (x, y) = (0,4.0 cm) in SI units. Represent your answer as a vector. Start with drawing a picture and setting up an appropriate coordinate system. b) Determine in what region along the x-axis it's possible for the electric field to be zero. There are three distinct regions: -o < x < x1, X1 < x < x2, and x2 < x < ∞ (this excludes x → ±∞ since the electric field is zero there). c) Now that you know in what region it's possible for the electric field to be zero, write out an expression you could solution to find exactly where this location is. Note: you DON'T have to solve it. d) Another charge (Q3 Newtons? Represent your answer as a vector. Hint: no need to apply Coulomb's law to Q3, you already know the electric field at this point. 4.0 µ C) is now placed at (x, y) = (0,4.0 cm). What is the net force on this…

A long, thin wire along the x-axis has a linear charge density of 8.8e-6 C/m. a) Find the magnitude of the electric field at point p a distance of 0.8 m from the wire. b) Find the magnitude of the net force on a test charge of 8e-6 C at point p. c) Which direction will the test charge accelerate? parallel to wire perpendicular to and toward wire perpendicular to and away from wire