6. Two +5.0 nC point charges are placed on the x - axis as shown below. y, cm a) Calculate the individual electric fields at point P2 due to i) q1 and ii) q2. b) Calculate the magnitude of net electric 4. field at point P, due to the two charges.[ 10 cm 3 2 c) Calculate the direction of the net electric field you calculated in part (b) -5.0 nC 5.0 nC above. X, cm

6.

1) Sketch the electric field lines on top of the figure above. Also sketch the electric field vector atpoint P. 2) Integrate to find the value of the electric field at point P.3) Find the force that would act on a 2.0 μC charge placed at point P.

Q3) Two point charges (Q = + 5.0 µC and Q2 = – 2.0 µ C) are held in place along the x-axis. Q, is at x1 = - 3.0 cm and Q, is at x2 = + 2.0 cm. a) Determine the electric field at (x, y) = (0,4.0 cm) in SI units. Represent your answer as a vector. Start with drawing a picture and setting up an appropriate coordinate system. b) Determine in what region along the x-axis it's possible for the electric field to be zero. There are three distinct regions: -o < x < x1, X1 < x < x2, and x2 < x < ∞ (this excludes x → ±∞ since the electric field is zero there). c) Now that you know in what region it's possible for the electric field to be zero, write out an expression you could solution to find exactly where this location is. Note: you DON'T have to solve it. d) Another charge (Q3 Newtons? Represent your answer as a vector. Hint: no need to apply Coulomb's law to Q3, you already know the electric field at this point. 4.0 µ C) is now placed at (x, y) = (0,4.0 cm). What is the net force on this…