Two point charges, +2.70 μC and -8.60 μC, are separated by 1.50 m. What is the electric potential midway between them?

Two point charges, Q1 = -5.00 μC and Q2 = +3.00 μC, are separated by 55.0 cm. Calculate the electric potential at a point midway between the charges.

Two point charges, +4.40 µC and -8.80 µC, are separated by 1.50 m. What is the electric potential midway between them? Number Units

A dipole consisting of charges +Q and -Q, with Q = 6.0 nC, is fixed to the y-axis. +Q is located at (0, 0.85 mm) and -Q is located at (0, -0.85 mm). What is the electric potential at a point 0 = 63° above the negative x-axis and r = 2.1m from the origin? ○ 0.019 V ○ -0.068 V ○ 0.038 V ○ 0.075 V -0.059 V

Two point charges, +3.90 μC and -8.90 μC, are separated by 3.50 m. What is the electric potential midway between them?

Consider charges placed at the corners of a rectangle: The value of the Coulomb constant is 8.98755 x 10⁹ Nm2/C2 and the acceleration of gravity is 9.8 m/s². P -0.35 m 6 μC + 0.25 m -9 μC -12 μC Find the electric potential at point P due to the grouping of charges at the other corners of the rectangle. Answer in units of V.

For a point charge, the equipotential surfaces form concentric spheres with the charges at the center. 2 such equipotential surfaces have potentials 293.3V and 95.2V. if these 2 concentric surfaces are separated by a distance of 2.2m, what is the charge of the point particle?

Two point charges, Q = +5.60 μC and q = −2.10 μC, are separated by 5.0 m. What is the electric potential energy?

Two point charges Q₁ = - -2.92 μC and Q2 = 2.52 µC are shown in the figure. Q₁ is located at (-2.1 cm, 0.0 cm) while Q2 is at (0.0 cm, — 2.6cm)). Use k = 9.0 × 10⁹ Nm²/C² (A) Find the electric potential at the origin. V = (B) If a -2.81 nC charge with a mass of 12.3 g is released from rest at the origin, how fast will it be moving when it is very far away from the charges? V = (C) If a proton is released from rest very far away from the charges shown above, how fast would it be moving at the origin? V =