For a point charge, the equipotential surfaces form concentric spheres with the charges at the center. 2 such equipotential surfaces have potentials 293.3V and 95.2V. if these 2 concentric surfaces are separated by a distance of 2.2m, what is the charge of the point particle?

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Given two particles with Q = 2.30-µC charges as shown in the figure below and a particle with charge q = 1.24 ✕ 10−18 C at the origin. (Note: Assume a reference level of potential V = 0 at r = ∞.) Three positively charged particles lie along the x-axis of the x y coordinate plane. Charge q is at the origin. Charge Q is at (0.800 m, 0). Another charge Q is at (−0.800 m, 0). (a) What is the net force (in N) exerted by the two 2.30-µC charges on the charge q? (Enter the magnitude.)  N (b) What is the electric field (in N/C) at the origin due to the two 2.30-µC particles? (Enter the magnitude.)  N/C (c) What is the electrical potential (in kV) at the origin due to the two 2.30-µC particles?  kV (d) What If? What would be the change in electric potential energy (in J) of the system if the charge q were moved a distance d = 0.400 m closer to either of the 2.30-µC particles?

Two point charges (nC and -15.50 nC) are located 8.00 cm apartLet U = 0 when all of the charges are separated by infinite distances. What is the potential energy if a third point charge q = - 4.2nC is placed at point b?