College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- A 5.70 x 10^-16 kg oil drop accelerates upward at a rate of 2.90 m/s^2 when placed between two horizontal, parallel plates that are 3.50 cm apart. If the potential difference between the plates is 7.92 x 10^2 V, what is the magnitude of the charge on the oil drop?arrow_forwardHow much energy is stored by the electric field between two square plates, 9.1 cm on a side, separated by a 2.3-mm air gap? The charges on the plates are equal and opposite and of magnitude 15 nC. Express your answer using two significant figures and include the appropriate units. PE = Value Units Submit Request Answer * Previous Next 15:10 hp W 27/03/2022 2000 hp f6 4 f11 10 F12 f10 f7 II f5 f8 f9 insert prt sc ( 9- ) 0 & -backspa // 大 t6arrow_forwardTwo uncharged spheres are separated by 2.70 m. If 2.00 ✕ 1012 electrons are removed from one sphere and placed on the other, determine the magnitude of the Coulomb force (in N) on one of the spheres, treating the spheres as point charges _______________Narrow_forward
- Levitation: The largest electric field strength you can create in air before dielectric breakdown (a spark) occurs is about 3.0 x 10°V/m. Suppose you created an electric field with this strength – pointing directly upward – between a set of parallel plates that are 9.9cm apart. You want to use this system to levitate water droplets with a mass of 1.8g. (a) How much charge would you have to put on a droplet to make it levitate? (b) Suppose that 43 charged droplets are levitating and the field strength suddenly drops by 24 percent, to about 2.3 x 106 V/m, how quickly would the droplets accelerate? Earrow_forwardWe assemble a group of three charges, each of + 2.0 µC, bringing them in from infinite distance, where we set V = 0. We put the first charge at x = 0 cm, then put the second one at x = 10 cm, and last put the third one at x = 20 cm. What was the total work done by the applied force? (Hint: At each step, W_applied = + Delta(PE) = + q Delta(V), where q is the charge you're bringing in now and V is determined by the charges that are already in place.)arrow_forwardTwo uncharged spheres are separated by 2.50 m. If 3.10 ✕ 1012 electrons are removed from one sphere and placed on the other, determine the magnitude of the Coulomb force (in N) on one of the spheres, treating the spheres as point charges.arrow_forward
- Two large, parallel, conducting plates are 11 cm apart and have charges of equal magnitude and opposite sign on their facing surfaces. An electrostatic force of 4.5 x 10-15 N acts on an electron placed anywhere between the two plates. (Neglect fringing.) (a) Find the electric field at the position of the electron. (b) What is the potential difference in volts between the plates? (a) Number i (b) Number i Units Unitsarrow_forwardTwo uncharged spheres are separated by 2.80m. If 3.70 ×10^12 electrons are removed from one sphere and placed on the other, determine the magnitude of the coulomb force on one of the spheres , treating the spheres as point charges.arrow_forwardTwo large, parallel, conducting plates are 9.5 cm apart and have charges of equal magnitude and opposite sign on their facing surfaces. An electrostatic force of 3.8 × 10-15 N acts on an electron placed anywhere between the two plates. (Neglect fringing.) (a) Find the electric field at the position of the electron. (b) What is the potential difference in volts between the plates? (a) Number i (b) Number i Units Unitsarrow_forward
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