Two parallel plates having charges of equal magnitude but opposite sign are separated by 11.0cm. Each plate has a surface charge density of 50.0 nC/m2. A proton is released from rest at the positive plate. Given information: Kinetic energy of proton when it reaches the negative plate = 9.94*10^(-17)J Potential difference between plates = 621.19V Magnitude of the electric field between the plates from the charge density = 5.647kN/C a) Determine the speed of the proton just before it strikes the

Physics for Scientists and Engineers, Technology Update (No access codes included)
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Chapter24: Gauss’s Law
Section: Chapter Questions
Problem 24.46P: A thin, square, conducting plate 50.0 cm on a side lies in the xy plane. A total charge of 4.00 108...
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Two parallel plates having charges of equal magnitude but opposite sign are separated by 11.0cm. Each plate has a surface charge density of 50.0 nC/m2. A proton is released from rest at the positive plate.

Given information:

Kinetic energy of proton when it reaches the negative plate = 9.94*10^(-17)J

Potential difference between plates = 621.19V

Magnitude of the electric field between the plates from the charge density = 5.647kN/C

a) Determine the speed of the proton just before it strikes the negative plate.

b) Determine the acceleration of the proton.

c) Determine the force on the proton.

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