Two identical pendulums are on the surface of Mars and Earth. The period of the Mars pendulum is longer than the one on Earth. Why? There is more friction from the Martian atmosphere. O The acceleration due to gravity on Mars is greater than that on Earth. The rotation of Mars affects a pendulum more than Earth. The acceleration due to gravity on Mars is less than that on Earth.

Two identical pendulums are on the surface of Mars and Earth. The period of the Mars pendulum is longer than the one on Earth. Why? There is more friction from the Martian atmosphere. O The acceleration due to gravity on Mars is greater than that on Earth. The rotation of Mars affects a pendulum more than Earth. The acceleration due to gravity on Mars is less than that on Earth.

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Description: Two identical pendulums are on the surface of Mars and Earth. The period of theMars pendulum is longer than the one on Earth. Why?There is more friction from the Martian atmosphere.O The acceleration due to gravity on Mars is greater than that on Ea

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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As the length of the pendulum increases, what happens to the total energy of the system? O decreases O it decreases and increases as the pendulum oscillates O remains the same O increases
3) OK, once again we have a pendulum, this time of length 1.94 m, which you release from rest at an angle of 59.1 degrees to the vertical. What will be the speed of the pendulum at the instant it reaches an angle of 29.6 degrees above the vertical? Question 2 options: 6.88 m/s 3.68 m/s 4.30 m/s 2.23 m/s 4) This, the length of the pendulum is 2.17 m. Now you start with the pendulum at 10.2 degrees with respect to the vertical, but rather than releasing it from rest, you give it a push downward. It swings to the other side, and reaches a maximum angle of 34.0 degrees with respect to the vertical. What must have been the initial speed of the pendulum just after you pushed it? 2.70 m/s 0.82 m/s 3.51 m/s 2.57 m/s
L (meoo (2.0)x O M 17. A simple pendulum consists of a mass M attached to a vertical string L. The string is displaced to the right by an angle e. When the pendulum is released from rest what is the speed of the ball at the lowest point? B) ZgL C) /2gL cos 0 D) 29L(1- cos®) A) 2 gL
Help thank you! An object is attached to an ideal spring of spring constant 2.61 N/m. The spring is initially in its relaxed position. The object is then released and oscillates about its equilibrium position. The motion is described by y= (5.55 cm) sin [(0.700 rad/s)f]. What is the maximum kinetic energy?
Oscillation: A 175 g glider on a horizontal, frictionless air track is attached to a fixed ideal spring of force constant, k=155 N/m. When it is 3.0 cm from the equilibrium position, it is moving at 0.815 m/s. What is the amplitude oscillation?
You want to create a pendulum clock (here on Earth) that will take 0.5 seconds to swing from one side to the other (which means it takes 1 second to go back and forth). How long should the pendulum be? O 1m O It depends on the mass of the pendulum bob О 25 ст 9.8 m 6 ст O It depends on the mass of the pendulum bob and the spring constant О 50 сm Continuing from the previous problem: You travel to Mars (where gravitational acceleration is 3.7 m/s-) and want to keep using your pendulum clock there (again, taking 0.5 seconds to swing from one side to the other). What adjustments do you need to make? O No adjustments are needed - the pendulum clock will still work properly on Mars. It's impossible nothing you do can get this pendulum clock to work on Mars Increase the mass of the pendulum bob O Make the string shorter Make the string longer O Decrease the mass of the pendulum bob O O O
A simple pendulum of length L, has a maximum angular displacement e_max. At one point in its motion, its kinetic energy is K = 3 Jand its potential energy is U = 4.2 J. When the pendulum's angular velocity is one-third its maximum value (e' = e'_max/3), then its kinetic energy is: O K = 0.45 J O K = 0.75 J O K= 1.8 J O K = 0.8 J O K= 1J
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into oscillation on a horizontal frictionless surface as shown in the figure. To put the system into oscillation, you pull You attach one end of a spring with a force constantk= 673 N/m to a wall and the other end to a n the block to a position x,= 7.36 cm from equilibrium and release it. (a) Determine the potential energy stored in the spring before the block is released. (b) Determine the speed of the block as it passes through the equilibrium position. m/s (c) Determine the speed of the block when it is at a position x/4. Hi m/s
1. A pendulum of length L = 0.80 m is released from B with a speed of 1.0 m/s as shown in the figure. Find the speed of the pendulum at the lowest point c. 30° B C
4.A simple pendulum has an oscillation frequency of 0.5 Hz, and a mass of 200 grams attached. At its greatest amplitude, the string forms an angle of 30 degrees. A) What is the greatest value of gravitational potential energy obtained by the mass? B) What is the fastest speed obtained by the mass?
Two simple harmonic oscillators H1 and H2 of masses on a spring have masses m1 and m2, spring constants k, and k2, and amplitudes A1 and A2. It is found that the total mechanical energy of H2 equals 4H1. Which one of the following will NOT give this relationship? O mị = m2 ; 4k1 = k2 ; A1 = A2 O 4m1 = m2 ; 4k1 = k2 ; A1 = A2 O mi = m2 ; 2k1 = k2 ; (v2) A1 = A2 O 4m1 = m2 ; ki = k2 ; Aı = A2