Two identical 43 mg dust particles very far apart (PEE ≈ 0) are moving directly toward each other at a speed of 9633 m/s. The charge on each is 540 ?C. Find how close they will get to each other. Let k = 9×109 N·m2/C2 & ignore gravity. B.) Two identical 31 mg dust particles 6.1 m apart are released from rest. The charge on each is 606 ?C . Find how fast they will be going when they are an infinite distance apart. Let k = 9×109 N·m2/C2 & ignore gravity.

A proton is fired from very far away directly at a fixed particle with charge q = 1.90 x 10-18 C. If the initial speed of the proton is 1.9 x 105 m/s, what is its distance of closest approach to the fixed particle? The mass of a proton is 1.67 x 10-27 kg. X The correct answer is not zero. m Submit Answer

Attached is the question and diagram.

A point charge, q = -8.0 µC, moves for a distance of 80 cm at an angle of 900 relative to the direction of a uniform electric field of strength 500 N/C. What is the magnitude of the change in potential energy for the charge?   a. 6.4 mJ   b. 9.6 mJ   c. 0.00 mJ   d. 3.2 mJ   e. 12.8 mJ

2e ++ 2003 Thomson Brooks Cole v=0 + Figure P16.19 + 79e + |—d — + + + + (c16p19) In Rutherford's famous scattering experiments (which led to the planetary model of the atom), alpha particles (having charges of +2e and masses of 6.64×10-27 kg) were fired toward a gold nucleus with charge +79e. An alpha particle, initially very far from the gold nucleus, is fired at 4.60×107 m/s directly toward the gold nucleus as in Figure P16.19. How close does the alpha particle get to the gold nucleus before turning around? Assume the gold nucleus remains stationary.

2. Consider the electric field formed from a point charge Q = 5 nC at the origin. A dipole is placed in this electric field at the Cartesian coordinate (1 m, 1 m), and its dipole moment is p=1 ŷ (C-m). a. what is the potential energy of the dipole? b. In what direction will the dipole begin to rotate?