Two converging lenses have 17.8 cm focal length, and are placed 16.12 cm apart. An object is placed 23.0 cm in front of one. Where will the final image formed by the second lens be located? Give your answer in cm to 3 decimals. Your Answer:

A photographer places a 1.75 cm high pearl 3.50 cm in front of a concave mirror. This results in a 5.50 cm high virtual image of the pearl appearing as if behind the mirror. What is the mirror's focal length (in cm)? |-5.13 X cm

= A doublet lens consists of two lenses in effective contact. The front lens is biconvex with fi +37.5 cm, and the second is biconcave with f2 = -150 cm. An object of height 2 cm is placed at 80 cm to the left of the combined lens. Calculate the position of the image, and the image height.

= 3. A 15 cm tall object sits 80 cm to the left of a converging lens with a focal length of fi 30 cm. There is a second converging lens with a focal length of f2 = 20 cm sitting 60 cm to the right of the first converging lens. dige de a. Where is the image from the first lens formed? (find di1) f₁ = 30 cm do = 80cm di = ? C. -14 1-do₂ 'वे di = [130 - 50 ] = 48 cm to the right of lens 1 = b. What is the object distance for the second lens? (find doz) f₂ =20 cm do=48 cm di = ? Where is the final image formed? (find diz) do d. What is the distance between the original object and the final image? What is the overall magnification for this two-lens system? f. What is the height of the final image? (find hi2) 2