College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- You have a thin, diverging lens. If the value of q (the distance from the image to the mirror along the principal axis of the mirror) is -3.57cm and the distance of p (the distance from the object to the mirror along the principal axis of the mirror) is 17.16cm, what is the focal length of the diverging lens? Object Ray 1 Principal focal point Virtual image Diverging lens Ray 1 Ray 3 Ray 2 Secondary focal point |fl ·|fl· Note: Do not explicitly include units in your answer (it is understood the unit is cm). Enter only a number. If you do enter a unit, your answer will be counted wrong.arrow_forwardPlease use lensmaker’s equation to design a double converging lens with 4 cm focal length.R1 = 10meters, refraction index of glass is 1.5. Calculate R2arrow_forwardA photographer places a 1.75 cm high pearl 3.50 cm in front of a concave mirror. This results in a 5.50 cm high virtual image of the pearl appearing as if behind the mirror. What is the mirror's focal length (in cm)? |-5.13 X cmarrow_forward
- How far from a converging lens with a focal length of 35 cmcm should an object be placed to produce a real image which is the same size as the object? Express your answer to two significant figures and include the appropriate units. dodo = nothingnothingarrow_forwardA 1.00-cm-high object is placed 4.30 cm to the left of a converging lens of focal length 8.45 cm. A diverging lens of focal length -16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position height cm ---Select--- cmarrow_forward= A glass lens with an index of refraction of n = 1.52 cm has a front surface with a radius of curvature of R₁ has a back surface with a radius of curvature of R₂ = -18.7 cm. What is the focal length of this lens? cm b. Is this lens converging or diverging? ONLY 1 ATTEMPT IS ALLOWED FOR THIS PART. ---Select-- 16.2 cm, andarrow_forward
- = 3. A 15 cm tall object sits 80 cm to the left of a converging lens with a focal length of fi 30 cm. There is a second converging lens with a focal length of f2 = 20 cm sitting 60 cm to the right of the first converging lens. dige de a. Where is the image from the first lens formed? (find di1) f₁ = 30 cm do = 80cm di = ? C. -14 1-do₂ 'वे di = [130 - 50 ] = 48 cm to the right of lens 1 = b. What is the object distance for the second lens? (find doz) f₂ =20 cm do=48 cm di = ? Where is the final image formed? (find diz) do d. What is the distance between the original object and the final image? What is the overall magnification for this two-lens system? f. What is the height of the final image? (find hi2) 2arrow_forwardTwo identical diverging lenses are separated by 18 cm. The focal length of each lens is -8.0 cm. An object is located 4.0 cm to the left of the lens that is on the left. Determine the final image distance relative to the lens on the right. cmarrow_forward1. How far from the object should the lens be held?arrow_forward
- An object is 19.5 cm from the center of a spherical silvered-glass Christmas tree ornament 6.20 cm in diameter. ▼ Part A What is the position of its image (counting from the ornament surface)? Follow the sign rules. Express your answer with the appropriate units. s' = Submit ▾ Part B m = HA Value Submit Request Answer What is the magnification of its image? VG ΑΣΦ Units Request Answer PYREX ? ?arrow_forwardThe image of the coin in the figure is magnified by a factor of M = 4.7 times, and is a distance d = 9.4 cm from the lens. What is the focal length (in cm) of the lens? cm iarrow_forwardq37 An object (height = 8.2 cm) and its image are on opposite sides of a converging lens. The object is located 19.0 cm from the lens. The image is located 5.5 cm from the lens. Determine the magnification. Enter the numerical part of your answer to two significant figures. Hint: Remember that the sign of the magnification is significant.arrow_forward
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