An object is placed a distance do = 7.0 cm in front of a negative (diverging) lens of focal length f = -16.0 cm. Where is the image formed relative to the lens position (positive to the right of the lens)? = d; = What is the image magnification? m = cm Is the image upright or inverted? inverted upright no image is formed Is the image real or virtual? no image is formed virtual real

The image formed by a concave mirror is inverted and located at a distance lal = 6 cm in front of it. What can you say about the nature of the image, and its size? can not be determined O real image and magnified virtual image and magnified O virtual image and reduced O real image and reduced

You have a thin, diverging lens. If the value of q (the distance from the image to the mirror along the principal axis of the mirror) is -3.57cm and the distance of p (the distance from the object to the mirror along the principal axis of the mirror) is 17.16cm, what is the focal length of the diverging lens? Object Ray 1 Principal focal point Virtual image Diverging lens Ray 1 Ray 3 Ray 2 Secondary focal point |fl ·|fl· Note: Do not explicitly include units in your answer (it is understood the unit is cm). Enter only a number. If you do enter a unit, your answer will be counted wrong.

An object is 20.8 cm to the left of a lens that has a focal length of +8.5 cm. A second lens, which has a focal length of -31 cm, is 5.28 cm to the right of the first lens. 1) Find the distance between the object and the final image formed by the second lens. cm 2) What is the overall magnification?