Two conductors made of the same material are connected across the same potential difference. Conductor A has three times the diameter and three times the length of conductor B. What is the ratio of the power delivered to A to the power delivered to B?

A 10.0 −μF capacitor is charged to a potential of 50.0 V and then discharged through a 185 −Ω resistor. How long does it take the capacitor to lose half of its charge? How long does it take the capacitor to lose half of its stored energy?

Three capacitors are connected in series. The equivalent capacitance of this combination is 3.27 µF. Two of the individual capacitances are 5.94 µF and 9.63 µF. What is the third capacitance (in µF)? 0.033 X HF Additional Materials M eBook A の stv W PDF MacBook Air 80 esc F2 F3 F4 FS F6 F7 F8 F9 * @ # 2$ % & 3 4 6. Q W E R T Y tab A S D F G J K caps lock C V VI * 00 つ エ B < CO

Consider the following figure. (Assume R₁ = 4.80 , R₂ = 7.90, and E = 20.0 V.) 1 + R₁ www 4.00 V + R₂ a -WW- 10.0 Ω b (a) Calculate the magnitude of the potential difference between points a and b in the figure above. X Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. V (b) Identify which point is at the higher potential. point a point b they are at equal potentials

The cell membranes of axons, which which are nerve cells in the human body, act as very small capacitors. A membrane is capable of storing 8.443e-9C of charge across a potential difference of 0.061V before discharging a nerve impulse. What is the capacitance of one of these axon membranes (in uF)?

The flash unit in a camera uses a special circuit to "step up" the 3.0 V from the batteries to 360 V , which charges a capacitor. The capacitor is then discharged through a flashlamp. The discharge takes 10 μs , and the average power dissipated in the flashlamp is 1.0×105 W .  What is the capacitance of the capacitor?

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A conducting sphere has a radius of 8.4 cm. A wire carries an electrical current of 1.3 μA into the sphere. How long will it take for the sphere to increase in potential to 1000V?

The most common cause of sudden cardiac arrest is ventricular fibrillation, an event in which the heart loses its electrical coordination. The only known cure for ventricular fibrillation is early defibrillation: a carefully timed electrical shock to the myocardium. The principal component of a defibrillator is a capacitor. It is charged by placing the switch in Position C in Figure 1. Rinternal power supply 3000 V O B. 15 A O A. 7.5A OD. 30 A O C. 22.5 A Figure 1 Schematic of a defibrillator The capacitor consists of a pair of metal plates separated by a dielectric. During defibrillation the switch is placed in Position D, discharging the capacitor through paddles pressed against the chest of the patient. Firm force (~100 N) and a conductive gel pad are used to improve the electrical contact between each paddle and the patient's chest. switch For successful defibrillation the current delivered must be maintained for several milliseconds. Because the current in an RC circuit decays…

Two capacitors, C1 = 5.92 µF and C2 = 3.30 µF, are connected in parallel, then the combination is connected to a 250 V battery. When the capacitors are charged, each one is removed from the circuit. Next, the two charged capacitors are connected to each other so that the positive plate of one capacitor is connected to the negative plate of the other capacitor. What is the resulting charge on each capacitor (in µC)? q′1= 421 µC q′2= 234 µC   (b) What If? What is the resulting charge on each capacitor (in µC) if they are instead charged as a series combination and then connected positive plate to positive plate and negative plate to negative plate? q′1= q′2=    solved the first two I need help with the bottom two it has to be in the format of the first two thank you