Triose phosphate isomerase In a key reaction of glycolysis, dihydroxyacetone phosphate (DHAP) is isomerized into glyceraldehyde 3-phosphate (G3P) by the action of the enzyme triose phosphate isomerase: CH₂OH C=0 CH₂OPO,²- DHAP CHO HC-OH CH₂OPO₂²¹ G3P AG" = +7.5 kJ/mol Because AG is positive, the equilibrium lies to the left. (a) Calculate the equilibrium constant for this reaction, assuming a temperature of 37 °C. (b) In the cell, depletion of G3P makes the reaction proceed. What is the value of AG if the concentration of G3P is kept at 1/100 of the value of the concentration of DHAP?

19. The AG, the standard free-energy change, for the isomerization of dihydroxyacetone phosphate (DHAP) to glyceraldehyde 3-phosphate (GAP) is +7.55 kJ/mol. The reaction shown below is catalyzed by an enzyme called Triose Phosphate Isomerase (TPI). OH O OH DHAP OH TPI OH M+ OH GAP OH This reaction takes place in glycolysis. At equilibrium, the ratio of GAP to DHAP is 0.0475 at 25°C and pH 7.00. Equilibrium constant, Keq = 0.0475. A) Is the above reaction endergonic or exergonic (going from left to right) under the given experimental conditions? Why? B) Can the above reaction occur spontaneously under the given experimental conditions? Why or why not?

Consider the following equilibrium at 25ºC :Glucose-1-Phosphate Glucose-6-PhophateUsing the equilibrium concentrations of [Glucose-1-Phosphate] = 0.35 M and [Glucose-6-Phosphate] = 1.65 M, calculate BOTH K′eqand Gº′ for this reaction. Is this reaction exergonicor endergonic? R = 8.314 J/K·mol

Determine the yield in water for the complete oxidation of 1 molecule of a triglyceride containing 3, C16 fatty acids. Please do not show the (7-C)-6 formula. Can you please show me where each water molecule comes from that is considered for this calculation (TCA, ETC, B-oxidation and ATP synthase)? Thank you!