Trials in an experiment with a polygraph include 99 results that include 22 cases of wrong results and 77 cases of correct results. Use a 0.01 significance level to test the claim that such polygraph results are correct less than 80% of the time. Identify th alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method. Use the normal distribution a an approximation of the binomial distribution. Let p be the population proportion of correct polygraph results. Identify the null and alternative hypotheses. Choose the correct answer below. O A. Ho p= 0.20 H, p+0.20 OC. Ho p= 0.20 H, p>0.20 O E. Ho p=0.80 H,: p<0.80 О В. На р0.80 H,: p> 0.80 O D. H p= 0.80 H, p#0.80 OF. Hoi p= 0.20 н, р<020 The test statistic is z =D (Round to two decimal places as needed.) The P-value is (Round to four decimal places as needed.) Identify the conclusion about the null hypothesis and the final conclusion that addresses the original claim. V H. There V sufficient evidence to support the claim that the polygraph results are correct less than 80% of the time.

A genetic experiment involving peas yielded one sample of offspring consisting of 441 green peas and 126 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 25% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. What are the null and alternative hypotheses? О А. Но: р30.25 В. Но: р3D0.25 H1: p#0.25 H1:p0.25 H1:p>0.25 F. Ho: p#0.25 H1: p<0.25 Е. Hо: р#0.25 H1:p=0.25 What is the test statistic? (Round to two decimal places as needed.)

find test statistic AND p value

A genetic experiment involving peas yielded one sample of offspring consisting of 400 green peas and 123 yellow peas. Use a 0.01 significance level to test the claim that under the same​ circumstances, 24​% of offspring peas will be yellow. Identify the null​ hypothesis, alternative​ hypothesis, test​ statistic, P-value, conclusion about the null​ hypothesis, and final conclusion that addresses the original claim. Use the​ P-value method and the normal distribution as an approximation to the binomial distribution What are the null and alternative​ hypotheses? What is the test​ statistic? What is the​ P-value? What is the conclusion about the null​ hypothesis?   What is the final​ conclusion?

In a survey1 of 1000 American adults conducted in April 2012, 43 % reported having gone through an entire week without paying for anything in cash. Test to see if this sample provides evidence that the proportion of all American adults going a week without paying cash is greater than 40 % . Use the fact that a randomization distribution is approximately normally distributed with a standard error of SE = 0.016 . Show all details of the test and use a 5 % significance level.

The p value & test statistic

What’s P value =??

In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6997 subjects randomly selected from an online group involved with ears. There were 1309 surveys returned. Use a 0.01 significance level to test the claim tha the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution. Identify the null hypothesis and alternative hypothesis. OA. Ho p#02 O B. Ho: p0.2 H p>02 H:p=0.2 OE. Ho p=02 OF. Ho: p=0.2 H p#02 Hip<0.2 The test statistic is z= (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) Because the P-value is the significance level, the null hypothesis. There is evidence to support the claim that the return rate is less than 20%.

In a random sample of 180 items, 11 are defective, resulting in manufacturing process defect rate of 6.1%. The manager claims that this is only a sample fluctuation and production is not really out of control. At the 0.01 level of significance, test the claim that the rate of defects is more than 3%, and thus the process is out of control. Null Hypothesis, HO Alternative Hypothesis, H1 Test Statistic, z P-value Significance level Conclusion

A genetic experiment involving peas yielded one sample of offspring consisting of 423 green peas and 125 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 27% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. C. Ho: p=0.27 H₁: p0.27 What is the test statistic? z = -2.21 (Round to two decimal places as needed.) What is the P-value? P-value 0.0272 (Round to four decimal places as needed.) What is the conclusion about the null hypothesis? D. Ho: p=0.27 H₁: p 0.27 OF. Ho: p 0.27 OA. Reject the null hypothesis because the P-value is less than or equal to the significance level, a. H₁: p=0.27 OB. Fail to reject the null hypothesis because the P-value is less than or equal to the significance…