In a study of cell phone usage and brain hemispheric​ dominance, an Internet survey was​ e-mailed to 6965 subjects randomly selected from an online group involved with ears. There were 1318 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than​ 20%. Use the​ P-value method and use the normal distribution as an approximation to the binomial distribution. Identify the null hypothesis and alternative hypothesis.

A brewery filling machine is adjusted to fill quart bottles with a mean of 32.0 oz of ale and a variance of 0.003. Periodically, a bottle is checked and the amount of ale is noted. a. Assuming the amount of fill is normally distributed, what is the probability that the next randomly checked bottle contains more than 32.02 oz? b. Let's say you buy 100 quart bottles of this ale for a party; how many bottles would you expect to find containing more than 32.02 oz of ale?

In a study of cell phone usage and brain hemispheric​ dominance, an Internet survey was​ e-mailed to 6971 subjects randomly selected from an online group involved with ears. There were 1319 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than​ 20%. Use the​ P-value method and use the normal distribution as an approximation to the binomial distribution.

In a study of cell phone usage and brain hemispheric dominance, an Intemet survey was e-mailed to 6992 subjects randomly selected from an online group involved with ears. There were 1294 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution. Identify the null hypothesis and alternative hypothesis. OA Ho p0.2 H1 p 0.2 O c. Ho p# 0.2 D. Ho: p 0.2 H p 0.2 H1 p 0.2 OE. Ho p 0.2 O F. Ho p 0.2 H1 p>0.2 Hy:p<0.2 The test statistic is z (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) the significance level, Because the P-value is the null hypothesis. There is evidence to support the claim that the return rate is less than 20%

In a study of cell phone usage and brain hemispheric​ dominance, an Internet survey was​ e-mailed to 6968subjects randomly selected from an online group involved with ears. There were 1335 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than​ 20%. Use the​ P-value method and use the normal distribution as an approximation to the binomial distribution.   Identify the null hypothesis and alternative hypothesis.   A. H0​: p=0.2 H1​: p≠0.2   B. H0​: p>0.2 H1​: p=0.2   C. H0​: p=0.2 H1​: p<0.2   D. H0​: p<0.2 H1​: p=0.2   E. H0​: p≠0.2 H1​: p=0.2   F. H0​: p=0.2 H1​: p>0.2   The test statistic is z= ____ ​(Round to two decimal places as​ needed.)   The​ P-value is ____. ​(Round to three decimal places as​ needed.)

In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6973 subjects randomly selected from an online group involved with ears. There were 1343 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution. ..... Identify the null hypothesis and alternative hypothesis. А. Но: Р0.2 ОЕ. Но: р> 0.2 OF. Ho:p=0.2 H4:p=0.2 H1:p<0.2 The test statistic is z= (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) Because the P-value is the significance level, the null hypothesis. There is evidence to support the claim that the return rate is less than 20%.

What’s P value =??

In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6997 subjects randomly selected from an online group involved with ears. There were 1309 surveys returned. Use a 0.01 significance level to test the claim tha the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution. Identify the null hypothesis and alternative hypothesis. OA. Ho p#02 O B. Ho: p0.2 H p>02 H:p=0.2 OE. Ho p=02 OF. Ho: p=0.2 H p#02 Hip<0.2 The test statistic is z= (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) Because the P-value is the significance level, the null hypothesis. There is evidence to support the claim that the return rate is less than 20%.

In a random sample of​ males, it was found that 21 write with their left hands and 210 do not. In a random sample of​ females, it was found that 56 write with their left hands and 440 do not. Use a 0.05 significance level to test the claim that the rate of​ left-handedness among males is less than that among females. Identify the test statistic. and p value

In a study of cell phone usage and brain hemispheric​ dominance, an Internet survey was​ e-mailed to 6983subjects randomly selected from an online group involved with ears. There were 1315 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than​ 20%. Use the​ P-value method and use the normal distribution as an approximation to the binomial distribution. Identify the null hypothesis and alternative hypothesis.     A. H0​: p=0.2 H1​: p>0.2   B. H0​: p>0.2 H1​: p=0.2   C. H0​: p=0.2 H1​: p≠0.2   D. H0​: p=0.2 H1​: p<0.2   E. H0​: p<0.2 H1​: p=0.2   F. H0​: p≠0.2 H1​: p=0.2   The test statistic is z=. ​(Round to two decimal places as​ needed.)   The​ P-value is . ​(Round to three decimal places as​ needed.)   Because the​ P-value is ▼ Less than, greater than   the significance​ level, ▼   reject fail to reject   the null hypothesis. There is ▼   sufficient…