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A: Here given four k map circuit We need to find minimized equation X for all k map
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A: For parallel resistance- 1Req=1R1+1R2+1R3+...... For series resistance- Req=R1+R2+R3+......
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A: Since the value of each resistor is not mentioned, we will assume that Each resistor value to be…
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A: The 5v voltage source in series with 5kΩ resistor is transformed into a 'I' current source parallel…
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A: Circuit diagram is given as, Here, all the points A,B,C,D are shorted so considered to be same…
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A: we will apply nodal analysis to find the node voltage then we will find the unknown current i1 .
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A: Types of transmission lines are as follows 1. Co-axial line 2. Two wire line 3. Optical fiber…
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A: The nyquist rate is the minimum sampling rate required to avoid aliasing, equals to twice the…
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Q: Determine the Current in the circuits, using Guass Jordan Elimination Method
A: Assume current directions in given circuit as Ix=I1Iy=I2-Iz=I3
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A: Given signal can we written as for n>0 xn=13nun you know by the formula xn =anun →Z.T. Xz…
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A: AND gate- In this gate we get high input only when both the inputs are high.
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- A 50 Hz, Scott connected transformer supplies an unbalanced two phase load at ( 400 V) per phase. For the leading phase the load has a resistance of (13.3 ohm) and capacitor of (318) micro farad in series. For the other phase the load consists of resistance (10) ohm and an inductance of (42.3) mH. Calculate both mathematically and graphically the lines currents on 3- phase side. The main transformer primary to secondary turns ratio is (12/1).Determine the short-circuit current ISC3,0.4kV for a 3-phase short- circuit fault at F. Give your answer up to 2 decimal in kA but do not enter the unit in your answer. Transformer T1 Transformer T2 Cable C1 Isc3,6.6kV Isc3.0.4kV O + j0.150 F 1 MVA 2 MVA 22/6.6kV 25 MVA fault level 6.6 kV/400V Z=3% 6.6 kV switchboard 400 V switchboardX₂=0.1 1 XL +03 Soto X₁ = 0.2 X = 0.1 X = 0.1 Above is the one-line diagram of a simple power system. Each generator is represented by an emf behind the subtransient reactance. All impedances are expressed in per unit on a common base. All resistances and shunt capacitance are neglected. The generators are operating on no load at their rated voltage with their emfs in phase. A symmetrical fault occurs at bus 1 through a fault impedance Z, =j0.08 per unit. a) Using Thevenin's Theorem, determine the impedance to the point of fault and the fault current in per unit. b) Find the bus voltages and line currents during the fault. 2 O oto
- A parallel connection of a RL branch with a C branch is connected across a 100V AC mains. At first R = 10 ohms, L = 20mH and frequency of 1000rad / s, the current measured is 2.2361A at 89.44 leading power factor. A) Determine the initial capacitance. B) However, a fault occurs on the capacitor branch making its capacitance 20% lower and a resistance of 5 ohms is detected. If this faulty circuit is rerun but at a frequency of 500 rad / s, determine the new current that will flow through the circuitDraw three transformers for each of the different three-phase connections. That is, draw three transformers and then make the connection, eg star-star, then redraw three transformers and make another three-phase connection, and so on until all four combinations of three-phase connections are made.3. Single-phase T1-transformer with a power of 500 kVA and a single-phase T2- with a power of 400 kVAtransformers are connected in parallel and load 1000 kVA with 0.8-back power factor.they are feeding. The equivalent circuit winding resistance of T1 is 0.025 b and the equivalent circuit reactance is 0.06is b. The equivalent winding resistance of T2 is 0.016 b and the equivalent circuit reactance is 0.07 b. Bothhas the same conversion ratio in the transformer.a. Draw the connection diagram given in the question. b. Obtain the power sharing expression over the parameters given in the question. c. Calculate the kVA values and power factors of the transformers.
- The circuit shows an unbalanced electrical installation powered by a positive sequence symmetrical three-phase network of 380 V compound voltage. The loads are single phase. Load 1 absorbs an active power of 950 W with f.d.p. 0.5 inductive. Load 2 absorbs an active power of 1,140 W with f.d.p. Unit. Load 3 absorbs from the network an active power of 760 W with f.d.p. 0.5 capacitive. Taking the network voltage URN as the phase reference, calculate: a) complex expressions of the line currents IR. Is. and ITThe circuit shows an unbalanced electrical installation powered by a positive sequence symmetrical three- phase network of 380 V compound voltage. The loads are single phase. Load 1 absorbs an active power of 950 W with f.d.p. 0.5 inductive. Load 2 absorbs an active power of 1,140 W with f.d.p. Unit. Load 3 absorbs from the network an active power of 760 W with f.d.p. 0.5 capacitive. Taking the network voltage URN as the phase reference, calculate: a) complex expressions of the line currents IR. Is. and IT RO- SO TO IR Is IT U₁-380 V CARGA 1 P₁ =950 W cos p1=0,5 ind. CARGA 2 P₂=1.140 W cos p₂=1 CARGA 3 P3=760 W cos p3=0,5 cap.Transkrmers phase with each bank with - adjuste 35. Three single-phase transformers, cach of 100 kVA rating, are conected in a closed-delta arrangement. If one of them is taken out, it would be possible to load the bank in such a manner that cach one is loaded to the extent of: A 86.6 kVA C. 57.7KVA B. 66.7 kVA D. 33.33 kVA when load is at unity power factor. 36. Average power factor at which V-V bank separate is A 86.6% C. 66.67% В. 73.3% D. None of these 37. Scott connections are used for: A. single-phase to three-phase transformation C. three-phase to two-phase transformation B. three-phase to single-phase transformation (D Any of the above 38. The current in low voltage winding of a 25 kVA, 6600/400 V, 50 Hz, 3-phase Y-A transformer, at full load is: A 36 A Č. 65,32 A B. 20.78 A D. 40.2 A 39. The current in high voltage winding of a 20 kVA, 2200/220 V, 50 Hz, 3-phase A-A transformer, at full load is: (A. 3.03 A C. jo.5 A B. 5.25 A D. None of above 40. The current in low voltage…
- A Cock-croft Walton type voltage multiplier has 7 stages with capacitance all equal 0.07pF. The supply a frequency of to be supplied is 6.5mA. to transformer secondary voltage is 133kV at 250HZ. If the load current The total voltage ripple of the system is: (a) 15.3kv (b) 12.2kv (c) 9.1kV (d) 10.4kv (e) 1.9kv a. d O b. a OC C O d. e O e. bProblem 1 - Series en Parallel AC networks [19] Look at the circuit in Figure 1 and determine the following: (a) Total Admittance. (b) Total Impedance. (c) Total Current (l:). (d) Current (I1) through impedance Z2. (e) Current (12) through impedance Z3. (f) Current (I3) through impedance Z4. (g) Is this an inductive or capacitive circuit? A. B Zs 220V;50HZ Figure 1 (h) Voltage across Z1. (i) Voltage across A and B. G) Voltage across Zs. Z1 = 3 + j5 ohm Z2 = 10 + jo ohm Z3 = 5 + j15 ohm Z4 = 10 – j30 ohm Zs = 20 – j30 ohm Admittance and Impedance in rectangular notation. All currents and voltage in polar notation. Take voltage as reference.H.W A 25 MVA, 13.8 KV synchronous generator with subtransient- reactance of 15% motors 10 MVA, 6.9 KV feeds two industrial reach with jo.950 pul 20 MVA, subtransient reactance, through a and 13.8/6.9 KV transformer with 5% reactance feeder of j0.05 p.u reuctances. All 25 MVA, 13.8 ICV (at gen) reactances are to k base. Determine the fault current and SCL at motor terminals for a 3 phase phase fault. 10 MVA Jo.05 30.05 O Leeder 25 MVA Xg=15% 13.81V 6.9 kv MI (M₂) 10 MVA