to solve the question please use the equations below. - a mass M moving with a velocity V1i collides with mass 2M moving with a velocity V2i. After the collision the first mass has a velocity V1f.make a diagram of the initial momemtub vectors and final momentum vectors in a (x,y) plane.determine the final velocity of the second mass in (I J K) notation.determine the final velocity of the second mass in terms of speed and angle.V1i=12 i -5J V2i= -3i +2J V1f= 8i +7J 0 = s/r@= @o + atConditions of staticΣ Fx = 0WavesVibrational motionT = 1/f@ = 2nfequilibriumVmax = Awv = fAfn = n fo@ = V/r0 = 0o+wot + ½ at²@ = sqrt(k/m)Σ Fx = 0CalorimetryIdeal gas law:Moment of inertia ofa = at/rPV = nRTv = sqrt(T/μ)In = 2L/nq=mc AT orA ring I MR²A sphere I = 2/5 MR²Σ Τ = Σ Tecwx(t) = A cos (wt + p)v(t) = -Aw sin (wt + p)a(t) = -Aw² cos(wt + p)amax = Aw²ac = w²rw² = wo² + 2 a(0-00)Fmax = m A 6²μ = mass/lengthq = AH mR = 8.314 L-kPa/mol-KA rodA disc I ¹2 MR²I = 1/3 ML² 180 degrees = à radiansVector componentsFor constant acceleration conditions:Newton's Second Laws of motionGravitational force, or weightFrictional forceHooke's lawCentripetal forceConservation of energyWorkGravitational potential energySpring potential energyKinetic energyImpulseMomentumMomentum conservationTorqueMoment of inertiause g = 10 m/s²Vx = V cos 0Vx² + V₂² = V²V = V0 + atd = do + vot + ½ at²v² = vo² + 2a(d-do)ΣF = maFg = mgF = ]NF = -kxFc = mv²/rΣ Ε; + W = Σ ΕW = F Ad coseUg = mghUs = ¹2 kx2¹KE = ¹2 mv² or 12 Iw2J = F AtVy = V sin 0tan 0 = Vy/Vxp = mv or L = IwΣ pi + J = Σ pfT = I a = Fr sin 0I = = Σ mr₁²

Name: to solve the question please use the equations below. - a mass M movin
Uploaded: 2024-03-20T06:57:37.000Z
Channel: Bartleby
Description: to solve the question please use the equations below. - a mass M moving with a velocity V1i collides with mass 2M moving with a velocity V2i. After the collision the first mass has a velocity V1f.make a diagram of the initial momemtub vectors and fin