2. Use the data below:Mg2+ + 2e- 2 MgE° = - 2.37 voltsZn²+ + 2e- = ZnE® = - 0.76 voltsFe2+ + 2e- 2 FeEJ = - 0.44 voltsPb2+ + 2e- 2 PbEo = - 0.13 voltsCu²+ + 2e- 2 CuE° = + 0.34 voltsAg+ + e- = AgE° = + 0.80 voltsto find the cell voltage, Ee-cell, for the cells involving:a. iron and leadb. zinc and copperc. magnesium and silver

Since we know that the species having larger reduction potential will be reduced easily And…

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to find the cell voltage, Ee-cell, for the cells involving:

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Potentiometric Titrations

Potentiometric titration is one of the important titration methods and is mainly carried out to characterize acid solutions. It follows a method similar to that of the normal titration technique, but the main difference is that there is no indicator used in the potentiometric titrations. Instead of using an indicator, electrodes are employed for monitoring the whole titration process. A scientist named Robert Behrend did the potentiometric titration for the first time, and it was done using the mercurous solution and potassium chloride.

Question

2. Use the data below:
Mg2+ + 2e- 2 Mg
E° = - 2.37 volts
Zn²+ + 2e- = Zn
E® = - 0.76 volts
Fe2+ + 2e- 2 Fe
EJ = - 0.44 volts
Pb2+ + 2e- 2 Pb
Eo = - 0.13 volts
Cu²+ + 2e- 2 Cu
E° = + 0.34 volts
Ag+ + e- = Ag
E° = + 0.80 volts
to find the cell voltage, Ee-cell, for the cells involving:
a. iron and lead
b. zinc and copper
c. magnesium and silver

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