QUESTION 15To find out how much fat is in a common hot dog, a nutritionist recorded the amount of fat in 100 grams of a random sample of 9 brands asfollows:55.56Assume that the underlying distribution of fat in grams is normal.a. Find the meandecimal places.b. Find the 95% confidence interval,your answer to two decimal places.6.25and the standard deviation6.7577.7588of the amount of fat. Round your answer to twofor the average amount of fat in the hot dog. Round

Given data is4,5,5.5,6,6.25,6.75,7,7.758,8sample size(n)=9

Answered: To find out how much fat is in a common…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The time taken for a computer to boot up, X, follows a mound-shaped (i.e. bell-shaped) distribution with a mean of 30 seconds and a standard deviation of 5 seconds. What is the standardized score for a boot up time of... a. x = 30 seconds? b. x = 20 seconds? c. x = 35 seconds? 1 Z-Score = Z-Score = Z-Score = h
The highway mileage (mpg) for a sample of 10 different models of a car company can be found below. 48 43 24 39 27 43 46 26 22 49 Find the mode: Find the range: Estimate the standard deviation using the range rule of thumb:
Chell is testing several types of boots for durability when falling a long distance. She found six types of boots. For each boot she drops from increasing heights until she is injured. Her overall average was 72.5 feet, with a pooled standard deviation of 6.4. The data for each type is shown below. Number ofboots Std Dev(for each boot) Mean height(in feet) Steel 24 6.9 69.5 Titanium 7 8.9 69.4 Vibranium 18 5.2 73.3 Mithril 8 5.9 74.5 Netherite 13 4.4 75.4 Atium 15 7.2 74.2 Assuming normality and equal variances perform a hypothesis test.Use three decimal places in the table
A company selling a new type of laptop battery advertises that it has a méan lifetime of 5 years. If you were in charge of quality control at the factory, which one of the following standard deviations of battery life spans would you prefer? 2 months. O 2 years O 5 years 27
After the pandemic hit and people were forced to spend more time indoors, there have been a suspicion among health professionals. that people are eating more and thus gaining weight. In 2018, the average weight of 192 pounds, and health experts want to know if that average weight of the American male has gone up during this pandemic. d. A sample of 50 American males yeilded a sample average weight of 195 pounds and a sample standard deviation of 14.5 pounds. What is your conclusion at the 5% level of significance? (be sure to state your conclusion in the context of this problem) e. Would your conclusion change if the level of significance were changed to 1%? Briefly explain.
2. 60 matches were played in a football tournament. The table to the right shows the number of goals scored in all matches. Number of Goals 1 3 4 5 Number of Matches 18 20 3 a. Find the median number of goals scored per match. b. Find the mean number of goals scored per match. c. Calculate the standard deviation of the goals scored per match.
Here are 11 values from a dataset: 0 0 0 1 2 2 3 4 6 6 6 The sample mean for this dataset is 2.73. Which of the following values is your best guess for the approximate size of the sample standard deviation for these 11 numbers: 1, 2.5, or 5? You may calculate the sample standard deviation for this set of data but it is not required. lp
Esp Heavy children: Are children heavier now than they were in the past? The National Health and Nutrition Examination Survey (NHANES) taken between 1999 and 2002 reported that the mean weight of six-year-old girls in the United States was 49.3 pounds. Another NHANES survey, published in 2008, reported that a sample of 193 six-year-old girls weighed between 2003 and 2006 had an average weight of 52 pounds. Assume the population standard deviation is o =16 pounds. Can you conclude that the mean weight of six-year-old girls in 2006 is different from what it was in 2002? Use the a =0.01 level of significance and the critical value method. 00 Part: 0/ 5 Part 1 of 5 (a) State the appropriate null and alternate hypotheses. H.: OD O=0 dl. H : This hypothesis test is a (Choose one) test. 00
You work for a soft-drink company in the quality control division. You are interested in the standard deviation of one of your production lines as a measure of consistency. The product is intended to have a mean of 12 ounces, and your team would like the standard deviation to be as low as possible. You gather a random sample of 17 containers. Estimate the population standard deviation at a 95% level of confidence. 11.94 11.99 11.97 11.95 11.85 12.1 12.07 12.16 12.13 12.1 12.01 12.1 11.95 12 11.93 11.96 12.1 (Data checksum: 204.31) Note: Keep as many decimals as possible while making these calculations. If possible, keep all answers exact by storing answers as variables on your calculator or computer. Round final answer to 4 decimal places. a) Find the sample standard deviation: b) Find the lower and upper x² critical values at 95% confidence: Lower: Upper: c) Report your confidence interval for o: (
In the 1992 presidential election, Alaska's 40 election districts averaged 2002 votes per district for President Clinton. The standard deviation was 566. (There are only 40 election districts in Alaska.) The distribution of the votes per district for President Clinton was bell-shaped. Let X = number of votes for President Clinton for an election district. (Source: The World Almanac and Book of Facts) Round all answers except part e. to 4 decimal places. Find the third quartile for votes for President Clinton. Round your answer to the nearest whole number.
find the actual percentage in the data set, sort the DRIVE variable and count how many of the data points are less than 25 out of the total 35 data points. That is the actual percentage. How does this compare with your prediction? Mean: 57.457 Standard deviation: 26.539 Predicted percentage: 0.110 Drive: 44 20 88 6 71 42 76 63 61 63 84 28 55 33 88 80 86 83 5 85 25 25 54 54 81 73 29 76 78 77 42 65 71 94 6
The average time spent in transportation of randomly selected 48 households is 80.7 minutes per day with a standard deviation of 22.5 minutes. Estimate the true variation of the time spent in transportation of all households. Select one: O a. 80.7 22.5 O b. V48 O C.22.5 O d. 22.52 e. 22.5

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