You are interested in finding a 95% confidence interval for the average commute that non-residential students have to their college. The data below show the number of commute miles for 11 randomly selected non-residential college students. Round answers to 3 decimal places where possible.
10 | 6 | 27 | 19 | 13 | 14 | 6 | 22 | 19 | 12 | 20 |
a. To compute the confidence interval use a T or Z distribution.
b. With 95% confidence the population
c. If many groups of 11 randomly selected non-residential college students are surveyed, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population mean number of commute miles and about percent will not contain the true population mean number of commute miles.
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- You are interested in finding a 95% confidence interval for the mean number of visits for physical therapy patients. The data below show the number of visits for 14 randomly selected physical therapy patients. Round answers to 3 decimal places where possible. 13 22 12 28 10 28 16 15 22 28 11 27 24 24 a. To compute the confidence interval use a distribution. b. With 95% confidence the population mean number of visits per physical therapy patient is between and visits. c. If many groups of 14 randomly selected physical therapy patients are studied, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population mean number of visits per patient and about percent will not contain the true population mean number of visits per patient.arrow_forwardHELP I NEED IN ONE HOUR.arrow_forwardData Set: 12 15 5 7 9 12 13 6 14 15 14 14 13 14 8 8 10 11 8 6 8 13 6 12 13 6 10 9 14 13 10 14 10 5 13 13 14 6 9 12arrow_forward
- You are interested in finding a 98% confidence interval for the mean number of visits for physical therapy patients. The data below show the number of visits for 11 randomly selected physical therapy patients. Round answers to 3 decimal places where possible. 18 6 28 15 15 16 9 8 28 15 17 a. To compute the confidence interval use a distribution. b. With 98% confidence the population mean number of visits per physical therapy patient is between and visits. c. If many groups of 11 randomly selected physical therapy patients are studied, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population mean number of visits per patient and about percent will not contain the true population mean number of visits per patient.arrow_forwardEmpathy among police officers influences how they interact with citizens and the likelihood that they receive complaints. Gender differences in levels of empathy in the general population are not large but male and female officers have been shown to have different interaction styles with the public; this may be due to the different empathy levels. After sampling officers and measuring their levels of empathy you find the following data. Males Females n = 6 n = 9 M = 31 M = 45 SS = 490 SS = 680 If you were going to make gender comparisons like this, which option would be the correct choice? Write A or B in the box. [a] Option A. Independent-measures t-test Option B. Repeated-measures t-testarrow_forwardYou are interested in finding a 98% confidence interval for the mean number of visits for physical therapy patients. The data below show the number of visits for 13 randomly selected physical therapy patients. Round answers to 3 decimal places where possible. 18 12 10 9 15 5 9 6 18 5 17 11 6 a. To compute the confidence interval use a distribution. b. With 98% confidence the population mean number of visits per physical therapy patient is between and visits. c. If many groups of 13 randomly selected physical therapy patients are studied, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population mean number of visits per patient and about percent will not contain the true population mean number of visits per patient.arrow_forward
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- Please fill in the empty boxes to B & Carrow_forwardYou are interested in finding a 90% confidence interval for the mean number of visits for physical therapy patients. The data below show the number of visits for 15 randomly selected physical therapy patients. Round answers to 3 decimal places where possible. 8 15 5 18 9 28 5 14 23 25 18 20 23 9 16 a. To compute the confidence interval use a distribution. b. With 90% confidence the population mean number of visits per physical therapy patient is between and visits. c. If many groups of 15 randomly selected physical therapy patients are studied, then a different confidence interval would be produced from each group. About ____percent of these confidence intervals will contain the true population mean number of visits per patient and about ____percent will not contain the true population mean number of visits per patient.arrow_forwardYou are interested in finding a 98% confidence interval for the mean number of visits for physical therapy patients. The data below show the number of visits for 11 randomly selected physical therapy patients. Round answers to 3 decimal places where possible. 27 5 28 22 15 9 16 10 25 18 5 a. To compute the confidence interval use a Z OR T distribution. b. With 98% confidence the population mean number of visits per physical therapy patient is between ? and ? visits. c. If many groups of 11 randomly selected physical therapy patients are studied, then a different confidence interval would be produced from each group. About ? percent of these confidence intervals will contain the true population mean number of visits per patient and about ? percent will not contain the true population mean number of visits per patient.arrow_forward
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