Through what potential difference (in kV) must an electron (starting from rest) be accelerated if it is to achieve a speed of 12.8×10 m/s? use e=1.6x10-19 C and me=9.11x10 31kg. Select one: O A. 77.38 O B. 19.87 O C. 46.64 OD. 28.78 O E. 142.44

Through what potential difference (in kV) must an electron (starting from rest) be accelerated if it is to achieve a speed of 12.8×10 m/s? use e=1.6x10-19 C and me=9.11x10 31kg. Select one: O A. 77.38 O B. 19.87 O C. 46.64 OD. 28.78 O E. 142.44

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: Four parallel plates are connected together in a vacuum. An electron is placed at hole A, where it…

A: To calculate the speed of the electron at hole B, we can use the conservation of energy. Assuming…

Q: B E = 1500 V/m x = -1.2 m x = +1.2 m x = 0.00 m 0 = A

Q: The speed of an electron moving along the y axis increases from 4.75 × 106 m/s at y= 10.0 cm to 8.00…

Q: If an proton is accelerated from rest througha potential difference of 74.2 V, what is its kinetic…

A: Given that:-Potential difference, ∆V0=74.2 VInitial speed of proton, u=0 m/s at restLet, charge on…

Q: What is the magnitude of the electric field at the point (3, 2) m if the electric potential is given…

Q: An electron in a picture tube of TV set is accelerated from rest through a potential difference of 5…

A: Basic physics concept.

Q: A computer monitor creates an image by accelerating electrons between parallel plates. If the…

A: Given, A computer monitor creates an image by accelerating electrons between parallel plates.…

Q: Across what potential difference must an electron, initially at rest, move to attain a speed of…

A: Particle = electron mass of electron (m) = 9.11×10-31 kg initial velocity (u) = 0 msfinal velocity…

Q: Through what potential difference (in kV) must an electron (starting from rest) be accelerated if it…

Q: An electron is accelerated from rest through a potential difference AV. If the electron reaches a…

Q: Oppositely charged parallel plates are separated by 6.06 mm. A potential difference of 600 V exists…

Q: Two parallel plates are situated 3.5 cm apart in vacuum and have a potential difference of 210 V…

A: Force on a charge q in an electric field E is given as: F=qE The electric field is given as the…

Q: apart. They are then Brought together, with a fiHal Separauon UI 3.3 IIII. How much work does it…

A: Electric potential energy is given as U=qV .......(1)…

Q: The speed of an electron moving along the y axis increases from 4.45 -10 m/s at y = 10.0 cm to 7.75…

A: a) As per the conservation law of energy, Here, E, K, U, m, v, q, and V represent the electron’s…

Q: If an proton is accelerated from rest througha potential differcnce of 74.2 V, what is its kinetic…

Q: Review Multiple-Concept Example 4 to see the concepts that are pertinent here. In a television…

A: Given data potential difference ∆V=16000V mass of the electronm=9.1×10-31kg charge of the electron…

Q: Particle 1 has mass 8.59 kg and charge 5.12 C. Particle 2 has mass 6.21 kg and charge -3.05 C. Find…

A: Electrostatic.

Q: Through what potential difference (in kV) must an electron (starting from rest) be accelerated if it…

A: We have to find the potential difference for an accelerated electron from rest as mentioned in the…

Q: Through what potential difference (in kV) must an electron (starting from rest) be accelerated if it…

A: Given data, Speed of the electron = 12.4x107 m/s Mass of an electron = 9.1x10-31 kg Charge of an…

Q: Review Multiple-Concept Example 4 to see the concepts that are pertinent here. In a television…

A: potential difference = 22000 V

Q: Calculate the speed of a proton in (m/s) that is accelerated from rest through an electric potential…

Q: James wants to store 2.50 J of electric potential energy in a volume of 1.00 m3 in a vacuum. To…

Q: A SYSTEM OF TWO ELECTRIC CHARGES b (in J) 92 91 What is the potential energy of this system of two…

Q: Through what potential difference (in kV) must an electron (starting from rest) be accelerated if it…

Q: A small particle has charge -4.10 μCμC and mass 1.80×10−4 kgkg. It moves from point AA, where the…

A: The given particle has a charge of -4.1 μC and a mass of 1.8×10-4 kg Let q=-4.1 μC=-4.1×10-6…

Q: If an electron is accelerated from rest through a potential difference of 9.9 kV, what is its…

Q: Ions of charge +2e and mass 96 amu (where e is the magnitude of the electron charge, and 1 amu =…

A: Givenq=2em=96 amu1 amu=1.66×10-27 kgV=290 kV(a)energy imparted=qV…

Q: A +6.00uC charge and -3.00uC charge are located on 2 vertices of an equilateral triangle with sides…

A: The equation for the electric potential at a point due to a point charge is given by

Q: An electron starts from rest and falls through a potential difference of 80.0 V. Calculate its final…

Q: Across what potential difference must an electron, initially at rest, move to attain a speed of 1.0…

Q: A particle with a mass of 1.50x10^-5kg and a negative charge of -9.00x10^-6C is constrained to move…

A: Mass of particle = 1.5*10^-5kg Negative charge (q) = -9*10^-6C V(x) = 3x^4 volt

Q: An electron moves with a velocity of 3.70 X106m/s to the right. Its speed is reduced to 1.40 X105m/s…

A: Q.Given that Initial velocity of the electron vi = 3.70 × 106 m/s Final velocity of the electron vf…

Q: The work done by an electric force in moving a charge from point A to point B is 2.05 x 103 J. The…

A: Work done W = 2.05 × 10-3J Potential difference VA- VB = 40.9 V

Q: 3. How much work must we do on an electron to move it from point A, which is at a potential of +50V,…

Q: A particle (m = 2.0 µg, q = -19 µC) has a speed of 30 m/s at point A and moves (with only electric…

A: Given: The mass is m=2 μg. The charge is q=-19 μC. The initial speed is vi=30 m/s. The final speed…

Q: Through what potential difference (in kV) must an electron (starting from rest) be accelerated if it…

A: We have to find the potential difference for an accelerated electron for the given problem. At…

Q: An electron is accelerated from rest through a potential difference of 3.00 kV. What is its final…

A: Given data: Initial velocity (u) = 0 m/s Potential difference (ΔV) = 3.00 kV Mass (m) = 9.109×10-31…

Q: In large CRT televisions, electrons are accelerated from rest by a potential differ of 19.17 kV and…

A: GivenPotential difference, V=19.17 kV=19.17×103 Vqe=1.602×10-19 Cme=9.11×10-31 Kg

Q: An electron is accelerated from rest through a potential difference AV. If the electron reaches a…

A: Given that:Electron accelerated from rest, u=0 m/sFinal speed, v=7×106 m/s

Concept explainers

Magnetic Field Of Coaxial Cable

The word coaxial means same axis. So for a long straight cable to be coaxial, it must have concentric cylindrical shaped conductor around it. Coaxial cable (popularly called ‘coax’) has various applications ranging from current conductors to radiofrequency signal transmitters. This cable has lower emission losses and provides protection from electromagnetic interference which allows signals with less power to transmit over longer distances.For example, currents produced in the pickup of a stereo turntable generally travel to the amplifier through a coaxial cable.The self-inductance of a coaxial cable is another important characteristic, because it influences the propagation of electrical signals in the cable.

Question

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

3a. What is the potential energy U of this lightning bolt? U = 310 Joules of the square? Find 30 (1.0x10) 3b. If all this energy where to be converted to kinetic energy, what would be the speed of a m = 1000 kg car. Vf = r16 = 34 = m/s 16. These charges are numbered as: raw the re Redraw the rectangle with the actual charges (evaluate 2q1, 492, etc.) 16a. What is the distance between the indicated pairs of charges. Find these in meters. r24 = r26 = 15 = 35 = 1 2 3 MI 4 5 6 ainT 16b. Starting with all the charges at ∞, what is the potential at the upper left corner, and how much work is done to put the charge at the upper left corner? V₁ = 05 P278 Volts W₁ = Joules V3 = V13 + V23 = | srpC = 10-12 C on m 16c. What is the potential at the location of 2, due to the previous charges? How much work is done to bring in the 2nd charge? Make sure you use the correct distance. V₂ = V12 = Volts W₂ = 16d. What is the potential at the location of 3, due to the previous charges? How much work is…
Calculate the speed of a proton in (m/s) that is accelerated from rest through an electric potential difference of 182 V. me-=9.11x 10-31kg m+=1.66 x 10-27kg 9e+ =9e-=1.6 x 10-19C Note: Answer will be in two decimal places
(a) Calculate the speed of a proton that is accelerated from rest through an electric potential difference of 144 V. 166.11*10^3 (b) Calculate the speed of an electron that is accelerated through the same potential difference. 7.12*10^6
An electron moving parallel to the x axis has an initial speed of 3.7 x 106 m/s at the origin. Its speed is reduced to 1.4 x 105 m/s at x = 2 cm. Calculate the electric potential difference 1. between the origin and x -= 2 cm. 2. A proton is released from rest in a uniform electric field whose magnitude is 5000 V/m. Through what potential difference will it have passed after moving 0.25 meters? How fast will it be going after it has travelled 0.25 meters?
Through what potential difference (in kV) must an electron (starting from rest) be accelerated if it is to achieve a speed of 7.4x10 m/s? use e=1.6x10-19 C and m.=9.11x1031kg. Select one: OA. 25.86 O B. 6.64 OC. 47.61 OD. 9.62 OE 15.59
Calculate the speed of a proton in (m/s) that is accelerated from rest through an electric potential difference of 149 V. m.-=9.11 x 10-31kg me+=1.66 x 10-27kg 9e+=9-=1.6 × 10-19C Note: Answer will be in two decimal places
A proton (mass = 1.67 x 10-27 kg, charge = 1.60 x 10-19 C) moves from point A to point B under the influence of an electrostatic force only. At point A the proton moves with a speed of 50 km/s. At point B the speed of the proton is 92.4 km/s. Determine the potential difference Vg-VA ( in units of volts). Select one: O A. 2.13 O B. 30.91 OC. -49.62 OD. 23.66 O E. -31.51 Next pag
What is the speed (in m/s) of a charge (mass = 2 x 10-8 kg, charge = 20µC) that has been accelerated from rest through a potential difference of 4.0 kV? Select one: O a. 3009 O b. 3311 O c. 3775 O d. 2828
I'm having trouble finding the solution to this problem. This problem is based off the textbook "Physics: Principles with Applications, 7th edition by Douglas C. Giancoli" chapter 16.
An electron moving parallel to the x-axis has an initial speed of 3.70 x 106 m/s at the origin. Its speed is reduced to 1.40 x 105 m/s at the point x = 2.00 cm. Calculate the potential difference between the origin and that point. Which point is at the higher potential?
Point charges qA = 6.0 nC is located at (2.00 m, 0) and qB = -2.5 nC is located at (0, 3.00 m). What is the electric potential at point P (0, 0), in Volts? 1.00 nC = 1.00 x 109 C. Use K = 9.00 × 10⁹ Nm²/c².
nid=8938&page=7 Find the electric potential energy (in units of J) stored in a system composed of two point chargesiq=75 pC dnd g2=153 µC when separated by a distance of 3.5 mm between them Select one: OA. 295.1 OB. 111.5 OC 180.3 OD. 54.1 OE 65.6