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Geometric Mean :
If there are X1, X2,...., Xn are n observations then the geometric mean is given by,
Geometric mean = (X1×X2×... ×Xi)1/n
Where,
n = number of observations.
Step by step
Solved in 2 steps
- 3. The amount of time (in minutes) it took each individual in a sample of athletes to run a mile was recorded. In this particular sample, most of the athletes were able to run the mile quickly, but there were a small number of athletes who were not fast runners and needed more time to complete the mile. Two measures of center were computed for this sample: 12.9 minutes and 9.5 minutes. One of these measures is the mean and one is the median. Which measure must be the mean? A. The mean is 9.5 minutes because the distribution of running times would be skewed to the left. B. The mean is 9.5 minutes because the distribution of running times would be skewed to the right. c. The mean is 12.9 minutes because the distribution of running times would be skewed to the left. D. The mean is 12.9 minutes because the distribution running times would be skewed to the right.Question 2. Crescent Oil has developed three new blends of gasoline and must decide which blend or blends to produce and distribute. A study of the miles per gallon ratings of the three blends is being conducted to determine if the mean ratings are the same for the three blends. Five automobiles have been tested using each of the three gasoline blends and the miles per gallon ratings; Automobile (Block) 12345 2 4 5 Type of Gasoline (Treatment) Blend X Blend Y Blend Z 31 30 29 33 26 30 29 29 31 25 29.8 30 29 28 Treatment Means a. Compute the analysis of variance for the randomized block design 28.8 29 26 28.4 Block Means 30.333 29.333 28.667 31.000 25.667Which of the following z-score values represents the location farthest from the mean? Question 21 options: z = +0.50 z = +1.00 Z=-1.00 z = -2.00
- 2. QUESTION It has been hypothesized that treatments of plastic used in optic lenses will improve wear. Four different treatments are to be tested. To determine whether any differences in mean wear exist among treatments, 28 castings from a single formulation of the plastic were made and 7 castings were randomly assigned to each of the treatments. Wear was determined by measuring the increase in "haze" after 200 cycles of abrasion (better wear being indicated by smaller increases). The data collected are reported in the accompanying table. Treatment A B 9.16 11.95 11.47 11.35 13.29 15.15 9.54 8.73 12.07 14.75 11.26 10.00 11.97 14.79 13.66 9.75 13.31 15.48 11.18 11.71 12.32 13.47 15.03 12.45 11.78 13.06 14.86 12.38 83.90 98.65 87.00 76.37 11.986 14.093 12.429 10.910A physical therapist wanted to know whether the mean step pulse of men was less than the mean step pulse of women. She randomly selected 54 men and 75 women to participate in the study. Each subject was required to step up and down a 6-inch platform. The pulse of each subject was then recorded. The following results were obtained. Two sample I for Men vs Women Mean 112.8 118.1 StDev SE Mean Men Women 95% Cl for mu Men - mu Women (-9.81, - 0.79) T-Test mu Men = mu Women (vs <) T= - 2,34 P = 0.0104 DF = 126 54 11.2 14.5 1.5 75 1.7 P-value = 0.0104 State the researcher's conclusion. Which of the following is correct? O A. Fail to reject Ho, there is sufficient evidence to conclude that the mean step pulse of men was less than the mean step pulse of women O B. Reject Ho, there is not sufficient evidence to conclude that the mean step pulse of men was less than the mean step pulse of women O C. Fail to reject Ho, there is not sufficient evidence to conclude that the mean step pulse of men…QI. Define the Statistics.
- Hellen has just started a new years competition for her local climbing gym. There are two categories for this competition: singles and group (18 people). The rules are simple, put in the most hours in one months time and you get a guided tour to climb Ten Sleep canyon. She knows from running this competition over the years that the number of hours climbers at her gym spend training during this competiton is approximately normal and their mean competition hours per month in the gym are 24 hrs with a standard devaition of 6 hrs. Singles Distribution: X~N( , ) Group Distribution: x̄~N( , ) The winning single participant last year was in the 97 th percentile.... how many hours did the winner accumulate over the month? One of Hellan's friends Dave put in 27.12 hours on the wall. What is the probablity that another individual will beat his time? If someone puts in between 25.5-32.1 hours on the wall they get a Mountain Goat shirt. What percent of the singles competitors is expected to…You work for an animal rescue organisation and you have recently found a female stray cat with 6 kittens. Because you are worried that the kittens may be underfed, you measure their weights (in grams). You collect the following data: 231, 185, 154, 182, 202, 220. Calculate the mean weight of these 6 kittens. (Provide your answer as a number rounded to the nearest integer.)You are comparing data from two similar experiments that have a mean of 53. Experiment A has a standard deviation of 3.4 and experiment B has a standard deviation of 1.5. What does this tell you about the data in the experiments?
- The state Government gives grants to low-income undergraduate students. According to the National Postsecondary Student Aid Study conducted by the U.S. Department of Education in 2008, the average Pell grant award for 2007-2008 was $2,600. We wonder if the mean amount is different this year for Pell grant recipients at San Jose State University. Suppose that we randomly select 50 Pell grant recipients from San Jose State University. For these 50 students, the mean Pell grant award is $2,450 with a standard deviation of $600. Let µ = the mean amount of Pell grant awards received by San Jose State University Pell grant recipients this year. We test the hypotheses: H0: μ = 2,600 , Ha: μ ≠ 2,600. The sample size is greater than 30, so a t-model is a good fit for the sampling distribution. What is the t-test statistic? What is the P-value?A SAMPLE SIZE OF 36 WAS DRAWN AND ITS MEAN WAS FOUND TO BE 80. TEST WHETHER THIS SAMPLE COULD HAVE COME FROM A NORMAL POPULATION WITH MEAN 90 AND VARIANCE 225? Your answerConsider the following data. 14,6,−11,−6,5,1014,6,−11,−6,5,10 Copy Data Step 1 of 3: Determine the mean of the given data.
