Three moles of gas initially at a pressure of 2.00 atm and a volume of 0.300 L has internal energy equal to 91.0 J. In its final state, the gas is at a pressure of 1.50 atm and a volume of 0.800 L, and its internal energy equals182 J. P (atm) 2.00 B. 1.50 V (liters) 0.300 0.800 (a) For the paths IAE, IBF, and IF in the figure above, calculate the work done on the gas. WIAF= W IBF = (b) For the paths IAF, IBF, and IF in the figure above, calculate the net energy transferred to the gas by heat in the process. QIAF= QIBF = QIF =

Physics for Scientists and Engineers: Foundations and Connections
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Chapter21: Heat And The First Law Of Thermodynamics
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Three moles of gas initially at a pressure of 2.00 atm and a volume of 0.300 L has internal energy equal to 91.0 J. In its final state, the gas is at a pressure of 1.50 atm and a volume of
0.800 L, and its internal energy equals 182 J.
P (atm)
IN
2.00
A
1.50
V (liters)
0.300
0.800
(a) For the paths IAF, IBF, and IF in the figure above, calculate the work done on the gas.
W,
IAF
W
IBF
WIF
(b) For the paths IAF, IBF, and IF in the figure above, calculate the net energy transferred to the gas by heat in the process.
QIAF =
QIBF
QIF=
Transcribed Image Text:Three moles of gas initially at a pressure of 2.00 atm and a volume of 0.300 L has internal energy equal to 91.0 J. In its final state, the gas is at a pressure of 1.50 atm and a volume of 0.800 L, and its internal energy equals 182 J. P (atm) IN 2.00 A 1.50 V (liters) 0.300 0.800 (a) For the paths IAF, IBF, and IF in the figure above, calculate the work done on the gas. W, IAF W IBF WIF (b) For the paths IAF, IBF, and IF in the figure above, calculate the net energy transferred to the gas by heat in the process. QIAF = QIBF QIF=
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